CODEWITHSUNDEEP
pythonpython-3.x
user9828149
user9828149

Reputation:

How to Ignore returning a key value in Python Dictionary

i need to write a function create_dictionary(filename) that reads the named file and returns a dictionary mapping from object names to occurrence counts (the number of times the particular object was guessed). For example, given a file mydata.txt containing the following:

abacus
calculator
modern computer
abacus
modern computer
large white thing
modern computer

Here's my program, and it works fine for non-empty text files.

from collections import Counter
def create_dictionary(filename):
"""Cool Program"""
   keys = Counter()
   s = open(filename,'r').read().strip()
   keys = (Counter(s.split('\n')))

dictionary = create_dictionary('mydata.txt')
for key in dictionary:
print(key + ': ' + str(dictionary[key]))
return keys

Out will be as:

{'abacus': 2, 'calculator': 1, 'modern computer': 3, 'large white thing': 1}

When I have an empty file (eg. blank.txt), the function must ignore any and all blank lines. So, the print statement must return a blank. But I am getting ': 1' no matter what I tried. And oh, here are some simple constraints: Here are some constraints:

Any advise?

Upvotes: 0

Views: 809

Answers (1)

John Gordon
John Gordon

Reputation: 33335

lines = open(filename,'r').readlines()
keys = Counter([line.strip() for line in lines if line.strip()])

Upvotes: 2

Related Questions