Reputation: 1078
okay, this might be a silly question.
So I have some tuples of size 4 so like (int,int,int,int)
If it were a 2 tuple I could use fst(myTuple) to refer to the first element. How could I, say, refer to the third element of a 4 tuple?
Upvotes: 4
Views: 1397
Reputation: 62975
Use pattern matching:
let tup = 1, 2, 3, 4
let _,_,third,_ = tup
printfn "%d" third // displays "3"
This is described directly in the MSDN documentation for tuples: Tuples (F#)
Upvotes: 9
Reputation: 22297
Here's a version of @Daniels novel solution which calculates Rest
offsets of the underlying Tuple representation to support position-based access on arbitrarily long tuples. Error handling omitted.
let (@) t idx =
let numberOfRests = (idx - 1) / 7
let finalIdx = idx - 7 * numberOfRests
let finalTuple =
let rec loop curTuple curRest =
if curRest = numberOfRests then curTuple
else loop (curTuple.GetType().GetProperty("Rest").GetValue(curTuple, null)) (curRest+1)
loop t 0
finalTuple
.GetType()
.GetProperty(sprintf "Item%d" finalIdx)
.GetValue(finalTuple, null)
|> unbox
//fsi usage:
> let i : int = (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36)@36;;
val i : int = 36
Upvotes: 5
Reputation: 47904
For the sheer novelty, here's an overloaded operator that works for tuples of any* size.
let (@) t idx =
match t.GetType().GetProperty(sprintf "Item%d" idx) with
| null -> invalidArg "idx" "invalid index"
| p -> p.GetValue(t, null) |> unbox
//Usage
let t = 4, 5, 6
let n1 : int = t@1 //4
let i = 2
let n2 = t@i //5
* Any, in this context, has a more limited meaning, specifically, up to 7.
Upvotes: 4
Reputation: 19339
If you want random access to a generally sized tuple, then it is not possible. For any given size, you can follow ildjarn's answer (extending it for four, five, etc.), but that it the only (functional) way.
A possibility for tuples in general, is to convert it to a list first, as found here, but that's not too pretty as it requires reflection.
Upvotes: 1