CODEWITHSUNDEEP
bashcurl
cchuter
cchuter

Reputation: 1

Bash adding extra single quotes to curl command defined as "...$'...'..."

This is very similar to Prevent bash from adding single quotes to variable output, but none of those answers are helping me.

This script:

set -ex

curl_headers=(
    --silent
    "--form release_description=$'\n new \n'"
)

curl "${curl_headers[@]}" "example.com"

Returns this output:

+ curl_headers=(--silent "--form release_description=$'\n new \n'")
+ curl --silent '--form release_description=$'\''\n new \n'\''' example.com

It's doing two things I don't want. It's adding a single tick before --form and it's escaping the single ticks in my release_description

The desired result is:

curl --silent --form release_description=$'\n new \n' example.com

How do I get it to remove the escape sequences and added single ticks?

Upvotes: 0

Views: 497

Answers (1)

chepner
chepner

Reputation: 532303

The single quotes are just how trace mode (from the -x option) displays the string; it doesn't affect your command at all. The main problem is that you are combining two separate arguments (--form and its argument) into one.

The correct script should be something like

set -ex

curl_headers=(
    --silent
    --form
    release_description=$'\n new \n'
)

curl "${curl_headers[@]}" "example.com"

Upvotes: 3

Related Questions