CODEWITHSUNDEEP
javascriptarrays
Oparah Dimkpa
Oparah Dimkpa

Reputation: 39

Return even and odd numbers between dynamic ranges in javascript

I am trying to write a code(function) that takes in two parameters a and b, and returns all the even number between a and b if a is greater than b else it should return the odd numbers between a and b.

this is my code.

function number_ranges (a, b) {

    let numbers = [];

    if (a > b){
        for (let i = b; i < a; i++){
            if (i > b){
                numbers.push(i);
            }
        }
    }else{
        for (let i = a; i < b; i++){
            if (i > a){
                numbers.push(i);
            }
        }
    }

    const result = numbers.filter(function(num){
        return a > b ? num % 2 === 0: num % 2 === 1;
    });
    return result;
}

I would like to see a different approach because i cant seem to be able to pass all the test cases

Upvotes: 0

Views: 992

Answers (2)

Luis felipe De jesus Munoz
Luis felipe De jesus Munoz

Reputation: 7923

I used this function f=(a,b)=>[...ArrayMath.max(a,b))].map((q,i)=>i).filter(z=>(a<b?!(z%2):z%2)&&z>=Math.min(a,b))

I first create a range from 1 to b as follow [...Array(Math.max(a,b))].map((q,i)=>i)

Then I filter with a<b?!(z%2):z%2. If a greater than b then a keep the even numbers, else the odds.

Also I keep only those number greater or equal to the first parameter using &&z>=Math.min(a,b)

f=(a,b)=>[...Array(Math.max(a,b))].map((q,i)=>i).filter(z=>(a<b?!(z%2):z%2)&&z>=Math.min(a,b))
console.log(f(10, 5))
console.log(f(5, 10))

Upvotes: 1

Nina Scholz
Nina Scholz

Reputation: 386654

You could take a sningle loop and a check if the value is even or or in combination with a check for the order.

function getEvenOdd(a, b) {
    var inc = +(a < b) || -1,
        i,
        result = [];
     for (i = a; i !== b + inc; i += inc) {
         if (+(inc === 1) !== i % 2) {
             result.push(i);
         }
     }
     return result;
}

// even
console.log(getEvenOdd(3, 10).join(' ')); // [4, 6, 8, 10]
console.log(getEvenOdd(4, 10).join(' ')); // [4, 6, 8, 10]
console.log(getEvenOdd(3, 9).join(' '));  // [4, 6, 8]
console.log(getEvenOdd(4, 9).join(' '));  // [4, 6, 8]

// odd
console.log(getEvenOdd(10, 3).join(' ')); // [9, 7, 5, 3]
console.log(getEvenOdd(10, 4).join(' ')); // [9, 7, 5]
console.log(getEvenOdd(9, 3).join(' '));  // [9, 7, 5, 3]
console.log(getEvenOdd(9, 4).join(' '));  // [9, 7, 5]

Upvotes: 1

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