CODEWITHSUNDEEP
regexsublimetext3
Justas Mundeikis
Justas Mundeikis

Reputation: 995

find multiple whitespaces in string

I'm trying to find all white spaces in string defined by begining as "jpeg" and ending with 600), in order to replace them with "_" but how do I catch all the \s in the string?

I'm working on sublime text editor / notepad++

I tried:

^jpeg.*(\s).*600\)$

Thanks for the help Example of text that is being edited: 

# CHART: Share of persons living at risk of poverty or social exclusion ====
df <- S3R0004_M3080242 %>% 
        mutate(LAIKOTARPIS=parse_date_time(LAIKOTARPIS, "y")) 
jpeg("./figures/Share of persons living at risk of poverty or social exclusion.jpeg", width = 9, height = 6, units = 'in', res = 600)
ggplot(data = df, aes(x=LAIKOTARPIS, y=obsValue)+

Upvotes: 0

Views: 105

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627087

You may use

Find what:      (?:\G(?!\A)|jpeg\("(?=[^"]*"[^)]*600\)))[^\s"]*\K\s+
Replace With: _

See the regex demo.

Details

  • (?:\G(?!\A)|jpeg\("(?=[^"]*"[^)]*600\))) - matches either
    • \G(?!\A) - the end of the preceding match
    • | - or
    • jpeg\("(?=[^"]*"[^)]*600\)) - jpeg(" followed with any 0+ chars other than " (with [^"]*), then " and then any 0+ chars other than ) and then 600)
  • [^\s"]* - matches and consumes 0+ chars other than whitespace and "
  • \K - match reset operator, the text matched before is cleared from the match buffer
  • \s+ - 1+ whitespaces (they will be replaced).

Upvotes: 1

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