Reputation:
Stuck on one aspect of a question for Computer Architecture I: Digital Design, and am not sure how to simplify (ABC')' or even (AB').
Not sure if any axiom or theorem can be applied, or if (ABC')' [or (AB')'] is the most simplified form. Can someone confirm?
Upvotes: 0
Views: 212
Reputation: 28312
To expand upon what Amadan said:
(AB')' + (ABC')'
A' + B + A' + B' + C DeMorgan applie twice
A' + A' + B + B'+ C commutativity of disjunction
A' + B + B' + C x + x = x
A' + 1 + C x + x' = 1
1 + C x + 1 = 1
1 1 + x = 1
Upon reflection this must be the case since B must be either true or false, and each of these values makes one or the other of the original terms true.
Upvotes: 0
Reputation: 198456
You can splat (ABC')'
into A' + B' + C
; similarly, (AB')'
is A' + B
(according to De Morgan's laws). These are disjunctive normal form.
Upvotes: 0