Reputation: 19
I have the following 3 tables;
Table_Names:
user_id Name
------------------
1 Mark
2 Tom
3 Ana
Table_Language:
language_id Language
-----------------------
1 English
2 German
Table_Name_Lang
id user_id language_id
---------------------------
1 1 1
2 1 2
3 2 1
4 3 2
How can I create a query to show the expected results like those below?
Name Expr_1_Eng Expr_1_Ger
---------------------------------
Mark English German
Tom English
Ana German
Thanks Tok
Upvotes: 1
Views: 49
Reputation: 1243
I think you should use pivot:
select n.name,[0] as language_one,[1] as language_two,[2],[3] from
(select n.name,tl.language
tablename n
left join Table_Name_Lang tnl on n.userid=tnl.userid
left join table_language tl on tl.id=tnl.id
group by n.name,tl.language
)T
pivot
(
language
for name in [0],[1],[2],[3]
)AS PivotTable;
Upvotes: 0
Reputation: 1269873
I would do:
select n.name,
max(case when l.language = 'English' then l.language end) as has_English,
max(case when l.language = 'German' then l.language end) as has_German
from names n join
name_lang nl
on nl.user_id = n.user_id join
lang l
on nl.language_id = l.language_id
group by n.name
Upvotes: 1
Reputation: 46219
You can try to use JOIN
with condition aggregate function
SELECT Name,
MAX(CASE WHEN tnl.language_id = 1 then tl.Language end),
MAX(CASE WHEN tnl.language_id = 2 then tl.Language end)
FROM
Table_Name_Lang tnl
JOIN Table_Names tn on tnl.language_id = tn.language_id
JOIN Table_Language tl on tl.user_id = tnl.user_id
GROUP BY Name
Upvotes: 0