Reputation: 29
I tried to run fastqc via a Snakemake command on my local computer. It didn’t work.
rule fastqc_raw:
input:
"raw/A.fastq"
output:
"output/fastqc_raw/A.html"
shell:
"fastqc {input} -o {output} -t 4"
It displayed this error:
Error in rule fastqc_raw:
jobid: 1
output: output/fastqc_raw/A.html RuleException: CalledProcessError in line 13 of
/Users/01/Desktop/Snakemake/Snakefile: Command ' set -euo pipefail;
fastqc raw/A.fastq -o output/fastqc_raw/A.html -t 4 ' returned
non-zero exit status 2. File
"/Users/01/Desktop/Snakemake/Snakefile", line 13, in __rule_fastqc_raw
File "/Users/01/miniconda3/lib/python3.6/concurrent/futures/thread.py",line 56, in run
However the snakemake program did created DAG file that looks normal and when I used “snakemake --np” command, it didn’t display any errors.
Upvotes: 2
Views: 752
Reputation: 75
An additional note: I can see you're using 4 threads there with the '-t 4' argument. You should specify this so Snakemake gives it 4 threads, otherwise I believe it will run with 1 thread and may fail due to lack of memory. This can be done like so:
rule fastqc_raw:
input:
"raw/A.fastq"
output:
"output/fastqc_raw/A.html"
threads: 4
shell:
"fastqc {input} -o {output} -t 4"
Upvotes: 0
Reputation: 21
I hope you have gotten an answer by now but I had the exact same issue so I will offer my solution.
The error is in the
shell:
"fastqc {input} -o {output} -t 4"
FastQC flag -o expects the output directory and you have given it an output file. Your code should be:
shell:
"fastqc {input} -o output/fastqc_raw/ -t 4"
Your error relates to the fact that the output files have been output in a different location (most likely the input directory) and the rule all: has failed as a result.
Additionally, FastQC will give an error if the directories are not already created, so you will need to do that first.
It is strange as I have seen Snakemake scripts that have no -o flag in the fastqc shell and it worked fine, but I haven't been so lucky.
Upvotes: 1
Reputation: 591
It looks like Snakemake did its job. It ran the command:
fastqc raw/A.fastq -o output/fastqc_raw/A.html -t 4
But the command returned an error:
Command ' set -euo pipefail;
fastqc raw/A.fastq -o output/fastqc_raw/A.html -t 4 ' returned
non-zero exit status 2.
The next step in debugging is to run the fastqc command manually to see if it gives an error.
Upvotes: 1