CODEWITHSUNDEEP
pythonmodulus
hs4545
hs4545

Reputation: 13

How do I check each number instead just the one value?

Divisors: For numbers from 2 to 100, print a series of lines indicating which numbers are divisors of other numbers. For each, print out “X divides Y”, where X <= Y, and both X and Y are between 2 and 100. The first few lines will be: 2 divides 2 3 divides 3 2 divides 4 4 divides 4 5 divides 5 etc.

So far I have this 

x = 2
y = 2
while y <= 100:
      while y <= 100:
            if y % x == 0:
                print(x, 'divides', y)
                y += 1
            elif y % x != 0:
                y += 1

Im not sure how to make it test the other values of x and y

Upvotes: 0

Views: 1182

Answers (3)

vash_the_stampede
vash_the_stampede

Reputation: 4606

You can use enumerate here and cycling through the indexes prior to every item will produce the results you are trying to get 

x = [*range(2, 101)]
for idx, item in enumerate(x):
    for i in x[:idx +1]:
        if not item % i:
            print('{} divides {}'.format(i, item))

2 divides 2
3 divides 3
2 divides 4
4 divides 4
5 divides 5
2 divides 6
3 divides 6
6 divides 6
...
99 divides 99
2 divides 100
4 divides 100
5 divides 100
10 divides 100
20 divides 100
25 divides 100
50 divides 100
100 divides 100

Upvotes: 0

Filip Matyja
Filip Matyja

Reputation: 137

This should do a work. Give it a try, if something is unclear give me a shout

x = int(input("Give the range you want to check numbers in: "))

for number in range(1,x):
    for value in range(1,number+1):
        if number % value == 0:
            print(number, " is divided by", value)

Output for input "10":

1  is divided by 1
2  is divided by 1
2  is divided by 2
3  is divided by 1
3  is divided by 3
4  is divided by 1
4  is divided by 2
4  is divided by 4
5  is divided by 1
5  is divided by 5
6  is divided by 1
6  is divided by 2
6  is divided by 3
6  is divided by 6
7  is divided by 1
7  is divided by 7
8  is divided by 1
8  is divided by 2
8  is divided by 4
8  is divided by 8
9  is divided by 1
9  is divided by 3
9  is divided by 9

Upvotes: 0

Sheldore
Sheldore

Reputation: 39062

Here is a corrected version of your code for a smaller value of y up to 6. You can extend it to 100.

Explanation: The first while loop checks for y value. For each y value, you check for its divisors using the second while loop which runs over x. You update x by 1 within the inner while loop and update y by 1 within the outer while loop. Comment below if something is unclear.

Problems with your code: You were using two while loops just for y, one of which was redundant. Moreover, you were not incrementing x as you clearly pointed out in your question. Your elif was also not required because you were incrementing y in both the cases.

y = 2
while y <= 6: # Replace 6 by 100 here
    x = 2 # Reset x to 2 for every y value because you count divisors from 2
    while x <= y:
        if y % x == 0:
            print(x, 'divides', y)
        x += 1  
    y += 1

Output

2 divides 2
3 divides 3
2 divides 4
4 divides 4
5 divides 5
2 divides 6
3 divides 6
6 divides 6

Upvotes: 1

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