Reputation: 13
Problem: I would like to get
(7,5,3) => 000001110000010100000011 => 460035
also the converse, i.e.,
460035 => 000001110000010100000011 => (7,5,3)
Here is the the program I have tried:
L=(7,5,3) # here L may vary each time.
a=0
for i in range(3):
a=bin(a << 8) ^ bin(L[i])
print a
But It gives error TypeError: unsupported operand type(s) for ^: 'str' and 'str'
How can I do this?
Upvotes: 1
Views: 1216
Reputation: 13737
There is no need to reinvent the wheel. If you'd seen the links to docs that I provided in the comments, you could find these useful methods there: int.from_bytes
and int.to_bytes
. We can use them like this:
input = (7, 5, 3)
result = int.from_bytes(input, byteorder='big')
print(result)
>>> 460035
print(tuple(result.to_bytes(3, byteorder='big')))
>>> (7, 5, 3)
Upvotes: 2
Reputation: 106945
You should perform bit operations on the numbers rather than the converted strings:
L=(7,5,3)
a=0
for i in L:
a <<= 8
a |= i
print(bin(a), a)
This outputs:
0b1110000010100000011 460035
Reversal:
a = 460035
L = []
while True:
L.append(a & 0xff)
a >>= 8
if not a:
break
L = tuple(L[::-1])
print(L)
This outputs:
(7, 5, 3)
Upvotes: 0