Reputation: 1021
I have:
myDict = {'a': [1,2,3], 'b':[4,5,6], 'c':[7,8,9]}
I want:
myDict = {'a': set([1,2,3]), 'b':set([4,5,6]), 'c':set([7,8,9])}
Is there a one-liner I can use to do this rather than looping through it and converting the type of the values?
Upvotes: 3
Views: 3882
Reputation: 432
You can't do it without looping anyway, but you can have the looping done in one line, with the following code:
myDict = {k:set(v) for k, v in myDict.items()}
This is basically traversing each item in your dictionary and converting the lists to sets and combining the key(str):value(set) pairs to a new dictionary and assigning it back to myDict variable.
Upvotes: 1
Reputation: 199
You can use comprehension for it:
Basically, loop through the key-value pairs and create set out of each value for the corresponding key.
>>> myDict = {'a': [1,2,3], 'b':[4,5,6], 'c':[7,8,9]}
>>> myDict = {k: set(v) for k, v in myDict.items()}
>>> myDict
{'a': {1, 2, 3}, 'b': {4, 5, 6}, 'c': {8, 9, 7}}
Upvotes: 1
Reputation: 4606
This can be done with map
by mapping the values to type set
myDict = dict(map(lambda x: (x[0], set(x[1])), myDict.items()))
Or with either version of dictionary comprehension as well
myDict = {k: set(v) for k, v in myDict.items()}
myDict = {k: set(myDict[k]) for k in myDict}
Upvotes: 1
Reputation: 44838
You'll have to loop anyway:
{key: set(value) for key, value in yourData.items()}
If you're using Python 3.6+, you can also do this:
dict(zip(myDict.keys(), map(set, myDict.values())))
Upvotes: 8