Reputation: 19734
I'd like to read and process 1024 bytes at a time in my file given by filename. I don't understand how to construct the outer loop correctly, especially to accommodate the final stride in which the buffer will contain fewer than 1024 bytes
What I have tried:
fs, _ := os.Open(filename)
defer fs.Close()
n := 1024 // 1kb
buff := make([]byte, n)
for {
buff = make([]byte, n) // is this initialized correctly?
n1, err := fs.Read(buff)
if err != nil {
if err == io.EOF {
break
}
fmt.Println(err)
break
}
fmt.Println("read n1 bytes...", n1)
fmt.Println(buff)
}
I have seen the following resources:
Upvotes: 3
Views: 17031
Reputation: 166935
Reading bytes into Go buffer with a fixed stride size
read and process 1024 bytes at a time in my file given by filename.
accommodate the final stride in which the buffer will contain fewer than 1024 bytes.
For number of bytes read guarantees, use ioutil.ReadFull
. For efficient stream reads, use bufio.Reader
. For efficiency, allocate the read buffer once and reuse it.
For example,
package main
import (
"bufio"
"fmt"
"io"
"io/ioutil"
"os"
)
func main() {
stride := 1024
filename := testname(stride)
f, err := os.Open(filename)
if err != nil {
fmt.Fprintln(os.Stderr, err)
return
}
defer f.Close()
r := bufio.NewReader(f)
buf := make([]byte, 0, stride)
for {
n, err := io.ReadFull(r, buf[:cap(buf)])
buf = buf[:n]
if err != nil {
if err == io.EOF {
break
}
if err != io.ErrUnexpectedEOF {
fmt.Fprintln(os.Stderr, err)
break
}
}
fmt.Println("read n bytes...", n)
// process buf
}
}
func testname(stride int) string {
f, err := ioutil.TempFile("", "test.stride.")
if err != nil {
panic(err)
}
defer f.Close()
_, err = f.Write(make([]byte, 2*stride+stride/2))
if err != nil {
panic(err)
}
return f.Name()
}
Playground: https://play.golang.org/p/iYOY-z7hkoz
Output:
read n bytes... 1024
read n bytes... 1024
read n bytes... 512
Upvotes: 7