Reputation: 67
Suppose I'm given a string "Nas". I want to select the char which has the highest integer value. How can I do this in Ruby?
My implementation involved creating a hash with the numerical value for each char:
alpha = {}
('a'...'z').zip(1. .26).each do |x| alpha[x[0]] = x[1] end
And then I'd loop through my word like so:
word.each_char do |c |
puts c
end
I have defined a method which takes two parameters, the first param is an array which specifies the "importance of a char", and second param takes a word:
def designer_pdf(h, word)
alpha = {}
('a'...'z').zip(1..26).each do |x|
alpha[x[0]] = x[1]
end
word.each_char do |c|
puts c
end
end
designer_pdf (
[1, 3, 1, 3, 1, 4, 1, 3, 2, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5],
'abc'
)
The goal is two return the highest value from the h
array based on the character from word
.
For example, word: 'abc'
:
a = 1
b = 3
c = 1
So return 3 because b is highest.
Upvotes: 0
Views: 335
Reputation: 110675
There is no need to construct a hash.
def largest_mapped_value(word, values)
base = 'a'.ord
values[word.each_char.max_by { |c| values[c.ord-base] }.ord-base]
end
# a b c d e f g h i j k l m n o p q r s t
values = [1, 3, 1, 3, 1, 4, 1, 3, 2, 5, 6, 5, 5, 7, 5, 5, 5, 5, 5, 1,
5, 5, 5, 5, 5, 5]
# u v w x y z
%w| cat kite zebra fined a |.each { |word|
puts "#{word}: #{largest_mapped_value(word, values)}" }
cat: 1
kite: 6
zebra: 5
fined: 7
a: 1
A variant is the following.
word = "fined"
base = 'a'.ord
#=> 97
word.each_char.map { |c| values[c.ord-base] }.max
#=> 7
Upvotes: 1
Reputation: 10251
You can pass any priority array
and any word
as arguments:
def designer_pdf(h, word)
alpha = Hash[('a'..'z').zip(h)]
# if you want only character from word with highest priority
character = word.chars.max_by{|e| alpha[e]}
# if you want only highest char value
value = alpha[character]
# if you want both character and value
[character, value]
end
> designer_pdf([1, 3, 1, 3, 1, 4, 1, 3, 2, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5], "abc")
#=> ["b", 3]
> designer_pdf([1, 3, 1, 3, 1, 4, 1, 3, 2, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5], "zeb")
#=> ["z", 5]
Upvotes: 2
Reputation: 6064
You can do this
For zep
string
p [*'a'..'z'].zip([1, 3, 1, 3, 1, 4, 1, 3, 2, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5])
.select{|x|("zeb".chars).include?x[0]}.max_by{|x|x[1]}
output
["z", 5]
Upvotes: 3