CODEWITHSUNDEEP
java
RIK
RIK

Reputation: 133

java.text.ParseException: Unparseable date: "11:00 PM, Sun 07 Oct 2018"

I have tried the code below, but it's not working.

Please explain why it's not working.

public static void main(String[] args) {
    String ti = "11:30 PM, Sun 07 Oct 2018";
    String sformat = "h:m a, E dd M yyyy";
    String cformat = "hh:mm a";
    String d = dateFormater(ti, cformat, sformat);
    System.out.println(d);
}

public static String dateFormater(String dateFromJSON,
                                  String expectedFormat, String oldFormat) {
    SimpleDateFormat dateFormat = new SimpleDateFormat(oldFormat);
    Date date = null;
    String convertedDate = null;
    try {
        date = dateFormat.parse(dateFromJSON);
        SimpleDateFormat simpleDateFormat = new SimpleDateFormat(expectedFormat);
        convertedDate = simpleDateFormat.format(date);
    } catch (Exception e) {
        e.printStackTrace();
    }

    return convertedDate;
}

Upvotes: 1

Views: 210

Answers (2)

Viswanath Lekshmanan
Viswanath Lekshmanan

Reputation: 10083

Your date format is incorrect. Please use the format below.

String sformat= "hh:mm a, EEE dd MMM yyyy";

Upvotes: 1

azro
azro

Reputation: 54168

Your pattern needs

  • MMM because the month is in short litteral format (M only is for month number and MMMM is for long litteral format)

    String sformat = "h:m a, E dd MMM yyyy";

And you should consider using new time API : java.time as it's easier to use and don't need extra mandatory try/catch : 

public static String dateFormater(String dateFromJSON, String expectedFormat, String oldFormat) {
    LocalDateTime date = LocalDateTime.parse(dateFromJSON, DateTimeFormatter.ofPattern(oldFormat, Locale.ENGLISH));
    String newStr = date.format(DateTimeFormatter.ofPattern(expectedFormat, Locale.ENGLISH));
    return newStr;
}

or in a single-line :

public static String dateFormaterSh(String dateFromJSON, String expectedFormat, String oldFormat) {
    return LocalDateTime.parse(dateFromJSON, DateTimeFormatter.ofPattern(oldFormat, Locale.ENGLISH))
                        .format(DateTimeFormatter.ofPattern(expectedFormat, Locale.ENGLISH));
}

Upvotes: 1

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