Reputation: 564
I have a program that is logging the time a user spends on certain aspects, some are identified as specific "time". I'm struggling to get multiple lines of Grouped query results into a single line for each month as a "summary".
My current query:
SELECT
TotalMins = SUM(Minutes)
,DateMonth = MONTH(Date)
,ID1
,PC
FROM User_Time_Log
WHERE
(UserID = 1)
AND (YEAR(Date) = 2018)
GROUP BY
MONTH(Date)
,ID1
,PC1
Current results:
TotalMins DateMonth ID1 PC1 192 1 0 0 306 1 0 100 113 2 0 0 365 2 0 100 14 2 1 0 3 2 1 100 75 3 0 0 253 3 0 100 3 3 1 0 300 4 0 0 233 4 0 100 10 4 1 0 23 4 1 100 438 5 0 0 134 5 0 100 19 5 1 0 49 5 1 100 0 9 1 0 11 10 0 0 21 10 0 60 167 10 1 100
What I would like to do from this point is to create a table showing all 12 months, regardless of whether there is information within that month or not, and show the relative information within each row for that month. for example:
DateMonth NonID1 TimeID1 TimePC1 (Round((PC1/100)*TotalMins)) TimePC1ID1 1 192 0 306 0 2 113 14 365 3 3 75 3 253 0 4 300 10 233 23 5 438 19 134 49 6 0 0 0 0 7 0 0 0 0 8 0 0 0 0 9 0 0 0 0 10 11 0 13 167 11 0 0 0 0 12 0 0 0 0
What's the most efficient way to do this?
Note: I have also created a table to give me 1-12 as rows that I can use to give me the months that I need to use, where information is not within the user_time_log.
Upvotes: 1
Views: 244
Reputation: 5707
Here's a simple way to do what you're looking for:
First, create your table of month values. I made a simple temp table with a single column.
CREATE TABLE #Dates (MonthNum INT)
INSERT INTO #Dates
(
MonthNum
)
VALUES (1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11),(12)
Next, you can put your existing query into a CTE, then LEFT JOIN
to your table of months. You'll want to put your columns into a SUM
'd CASE
statement, like so:
;WITH Aggregation AS
(
SELECT
TotalMins = SUM(Minutes)
,DateMonth = MONTH(Date)
,ID1
,PC1
FROM #User_Time_Log
WHERE
(UserID = 1)
AND (YEAR(Date) = 2018)
GROUP BY
MONTH(Date)
,ID1
,PC1
)
SELECT
d.MonthNum
,NonID1 = SUM(CASE WHEN ID1 = 0 THEN TotalMins ELSE 0 END)
,TimeID1 = SUM(CASE WHEN ID1 = 1 THEN TotalMins ELSE 0 END)
,TimePC1 = SUM(CASE WHEN ID1 = 0 THEN ROUND((PC1/100)*TotalMins,0) ELSE 0 END)
,TimePC1ID1 = SUM(CASE WHEN ID1 = 1 THEN ROUND((PC1/100)*TotalMins,0) ELSE 0 END)
FROM #Dates d
LEFT JOIN Aggregation a ON d.MonthNum = a.DateMonth
GROUP BY d.MonthNum
Output would then look like this:
MonthNum NonID1 TimeID1 TimePC1 TimePC1ID1
1 498 0 306 0
2 478 17 365 3
3 328 3 253 0
4 533 33 233 23
5 572 68 134 49
6 0 0 0 0
7 0 0 0 0
8 0 0 0 0
9 0 0 0 0
10 32 167 0 167
11 0 0 0 0
12 0 0 0 0
EDIT:
The ROUND()
function call can be changed slightly to accomodate your need for decimal results. The first parameter of ROUND()
is the expression you want to round, and the second is the number of decimal places to round to. Positive numbers indicate the number of places to the right of the decimal to round to. Negative numbers indicate the number of places to the left of the decimal to round to. So if you set it to 2
, you'll get an answer rounded to the nearest hundredth.
But there's one more tweak we need. PC1
and TotalMins
are both assumed to be INT
s in my answer. So we have to give the SQL engine a little help so that it calculates the answer as a DECIMAL
. By CAST()
ing the INT
s to DECIMAL
s, SQL will perform the arithmetic op as decimal math instead of integer math. You'd just have to change TimePC1
and TimePC1ID1
like so:
,TimePC1 = SUM(CASE WHEN ID1 = 0 THEN ROUND((CAST(PC1 AS DECIMAL)/100)*CAST(TotalMins AS DECIMAL),2) ELSE 0 END)
,TimePC1ID1 = SUM(CASE WHEN ID1 = 1 THEN ROUND((CAST(PC1 AS DECIMAL)/100)*CAST(TotalMins AS DECIMAL),2) ELSE 0 END)
Then the output looks like this:
MonthNum NonID1 TimeID1 TimePC1 TimePC1ID1
1 498 0 306.000000 0.000000
2 478 17 365.000000 3.000000
3 328 3 253.000000 0.000000
4 533 33 233.000000 23.000000
5 572 68 134.000000 49.000000
6 0 0 0.000000 0.000000
7 0 0 0.000000 0.000000
8 0 0 0.000000 0.000000
9 0 0 0.000000 0.000000
10 32 167 12.600000 167.000000
11 0 0 0.000000 0.000000
12 0 0 0.000000 0.000000
Upvotes: 1