CODEWITHSUNDEEP
pythonpython-3.xfunctiondictionaryrange
Gvido Kārlis Šķuburs
Gvido Kārlis Šķuburs

Reputation: 11

Range Function in Dictionary

example from this dog chart

My goal is:

def DogYears():
    small_dog = {
    1 : 15,
    2 : 24,
    3 : 28,
    4 : 32,
    5 : 36
    6 : 40
    .
    .
    .
    }

My question is how could I automate this process so that I don't have to fill it manually?

I was thinking of something like this, at least in that direction, of course it doesn't work:

def DogYears():
    small_dog = {
    range(15, 80, 4)
    }

I somehow also need to assign key & value pair. Any ideas?

Upvotes: 1

Views: 315

Answers (4)

slider
slider

Reputation: 12990

Ok, based off of Eduardo's answer, I think I have an equation. You don't need a dictionary:

def small_dog_years(age):
    if age <= 1: return 15
    return min(24 + (age - 2) * 4, 80)

print(small_dog_years(1)) # 15
print(small_dog_years(2)) # 24
print(small_dog_years(3)) # 28
print(small_dog_years(4)) # 32
print(small_dog_years(8)) # 48
print(small_dog_years(15)) # 76

You could then generate your dictionary (if you still wanted to) with a dict comprehension:

small_dog = {i: small_dog_years(i) for i in range(1, 17)}
print(small_dog)
>>> {1: 15, 2: 24, 3: 28, 4: 32, 5: 36, 6: 40, 7: 44, 8: 48, 9: 52, 10: 56, 11: 60, 12: 64, 13: 68, 14: 72, 15: 76, 16: 80}

Upvotes: 0

vash_the_stampede
vash_the_stampede

Reputation: 4606

You could use a dictionary constructor with the ranges that include the human years and dog years, you would have to add in the outlier 15, which would come at the end, if you need the dictionary properly sorted you could then just sort it as well using lambda. Also you need to extend your ranges by 1 unit since they are not inclusive.

small_dog = dict(zip(range(2, 17), range(24, 84, 4)))
small_dog[1] = 15
small_dog = dict(sorted(small_dog.items(), key=lambda x: x[0]))
# {1: 15, 2: 24, 3: 28, 4: 32, 5: 36, 6: 40, 7: 44, 8: 48, 9: 52, 10: 56, 11: 60, 12: 64, 13: 68, 14: 72, 15: 76, 16: 80}

Upvotes: 0

Karl
Karl

Reputation: 1714

Using a list allows you to have the ages keep a normal order and access the values by their index. Since all your keys only increase by one, then using a list would be a more appropriate data structure. You can just store your range() result into a list variable. Then to access the correct year, you can get the age like I did in the GetAge function passing in the year and list.

def DogYears():
    small_dog = range(15, 80, 4)

def GetAge(year, dog_list):
    index = year - 1
    if index >= 0 and index < len(dog_list):
        return dog_list[index]

Upvotes: 1

Eduardo Soares
Eduardo Soares

Reputation: 1000

If you want to build a dictionary, a simple foris enough. 

   def DogYears():
      small_dog = {}
      small_dog[1] = 15
      i = 2
      for j in range(24, 80, 4):
        small_dog[i] = j
        i = i + 1

Upvotes: 1

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