Reputation: 7
I have created a Servlet using GENERIC SERVLET which is working fine on port 8080 But now i have CREATED another html web form file to accept the input parameters from users, and then i created a Register Servlet(for that to accept the parameters from html page) using get parameter() method, and so that this file can accept the web form data, but when i made my request through html form data, it should accept the parameters and show the results, but instead , it says "404 Not Found" Intellij Idea.. I'm using Tomcat as a webserver
PLEASE HELP ME, Iam including some screenshots and program code..
Program code for HTML :- MY HTML CODE HERE
HTML PAGE TO ACCEPT USER FORM DATA
MAY BE I don't know how to manage ports ?..
Upvotes: 0
Views: 138
Reputation: 7
done !, i just changed the url to localhost:8080/Register and it works !
actually the file Register servlet was listening to port 8080 and the html file was forcing to go to the invalid url –
Upvotes: 0
Reputation: 954
Your post url is wrong. It should be /yoyo/web/Userinfoservlet instead of just /Userinfoservlet
Upvotes: 1