CODEWITHSUNDEEP
pythongetattr
MetaStack
MetaStack

Reputation: 3696

can you use getattr to call a function within your scope?

I'm trying to do something like this, but I can't figure out how to call the function bar.

def foo():
    def bar(baz):
        print('used getattr to call', baz)
    getattr(bar, __call__())('bar')

foo()

Notice, that this is somewhat unusual. Normally you'd have an object and get an attribute on that, which could be a function. then it's easy to run. but what if you just have a function within the current scope - how to do getattr on the current scope to run the function?

Upvotes: 3

Views: 1253

Answers (2)

Tryph
Tryph

Reputation: 6209

alternatively, you can also use the locals() function which returns a dict of local symbols:

def foo():
  def bar(baz):
    print('used getattr to call', baz)
  locals()['bar']('pouet')

foo()

It also allows you to get the function by its name instead of its reference without need for a custom mapping.

Upvotes: 3

Ajax1234
Ajax1234

Reputation: 71451

You are close. To use getattr, pass the string value of the name of the attribute:

getattr(bar, "__call__")('bar')

i.e

def foo():
  def bar(baz):
    print('used getattr to call', baz)
  getattr(bar, "__call__")('bar')

foo()

Output:

used getattr to call bar

Upvotes: 3

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