CODEWITHSUNDEEP
pythonpython-3.xlistdictionarymapping
Jeff Pernia
Jeff Pernia

Reputation: 79

Make a subset dictionary from another dictionary

Here's my issue , hope someone can help I have what I call a global dictionary which in my scenario is a dictionary of all the possible key:values in my program

global_dict = dict(zip(legend_values_global, legend_colors_global))

and the values look something like this 

{1: (191, 0, 0), 2: (191, 176, 0), 3: (29, 191, 0), 5: (0, 191, 147), 6: (0, 58, 191), etc

but now I need to make a dictionary of only the values that I need for a specific list. So if like X has only the values 1 2 and 3 then I want a new dictionary that looks like 

{1: (191, 0, 0), 2: (191, 176, 0), 3: (29, 191, 0)}

I do have a list called uniqueBins which has a list of tuples of the possible keys for each iteration

below is what I tried but I keep getting a Key Error

legend_colors_global = create_colors(len(legend_values_global))
        for bracket in bins:
            uniqueBins.append(tuple(sorted(set(bracket))))

        global_dict = dict(zip(legend_values_global, legend_colors_global))
        for i in range(waferNum):
            this_wafers_legend = {k: global_dict[k] for k in uniqueBins}

The format of uniqueBins is as follows:

[(1, 2, 3) ,(5, 10, 11), (1,7,8)]

The line this_wafers_legend = {k: global_dict[k] for k in uniqueBins} is the one failing but I'm not sure why. Any suggestions would be greatly appreciated.

Upvotes: 0

Views: 38

Answers (1)

vash_the_stampede
vash_the_stampede

Reputation: 4606

The problem is here : 

{k: global_dict[k] for k in uniqueBins}

uniqueBins is [(1, 2, 3), (5, 10, 11), (1, 7, 8)] so k for k in uniqueBins is an entire tuple which ends up being {(1, 2, 3): global_dict[(1, 2, 3)]}. You can just create your dictionary using k for k in uniqueBins[0] if your target is keys 1, 2, 3

uniqueBins = [(1, 2, 3), (5, 6, 2), (1, 3, 6)] # modified for provided data

this_wafers_legends = []
for i in uniqueBins:
    this_wafers_legends.append({k : global_dict[k] for k in i})

print(this_wafers_legends)
# [{1: (191, 0, 0), 2: (191, 176, 0), 3: (29, 191, 0)}, {5: (0, 191, 147), 6: (0, 58, 191), 2: (191, 176, 0)}, {1: (191, 0, 0), 3: (29, 191, 0), 6: (0, 58, 191)}]

Upvotes: 1

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