CODEWITHSUNDEEP
python
Nova
Nova

Reputation: 13

How to get only hour and seconds using localtime() in Python

How do I get hour and seconds separate using this..

localtime = time.asctime(time.localtime(time.time()))
print(localtime)

This results in this..

Thu Oct 11 17:23:28 2018

I just need to know how to get the hour and seconds separate, and if that's not possible with localtime() then how else could I do it?

I'm not that good at coding but am trying to work on a project and can't find any informative documentation on what I need.

Upvotes: 0

Views: 2359

Answers (3)

Sean Jungbluth
Sean Jungbluth

Reputation: 29

import time

secondVariable=time.localtime()[5]

hourVariable=time.localtime()[3]

Upvotes: 0

noname1014
noname1014

Reputation: 101

You can use the built in split function, which splits strings into array elements by checking for patterns. Default is ' ', e.g.

'abc def'.split()

will return

['abc', 'def']

So, applying this:

localtime = localtime.split()

will return:

['Thu','Oct','11','17:23:28','2018']

we want to extract the 4th element of the array, and arrays start at 0, so:

localtime = localtime[3]

this returns:

'17:23:28'

now, we need to split again, this time the ':' character:

localtime = localtime.split(':')

this returns:

['17','23','28']

now, for the last part:

extract the individual values:

hour = localtime[0]
minute = localtime[1]
second = localtime[2]

Upvotes: 0

Alex Taylor
Alex Taylor

Reputation: 8843

The time.strftime function is what you're after:

Convert a tuple or struct_time representing a time as returned by gmtime() or localtime() to a string as specified by the format argument.

To get the required output, use the following format string:

>>> import time
>>> time.strftime("%a %b %d %H:%M %Y", time.localtime())
'Thu Oct 11 17:23:28 2018'

Upvotes: 2

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