Reputation: 47
My MainActivity
contains a GoogleSignIn
button which pops up a menu with all the google accounts on the device. All works fine. The user is able to log in successfully, and directed to a new Activity.
Now, the new Activity (Main2Activity
) contains a log-out button, which redirects the user to MainActivity again. But when I click on GoogleSignIn
button again, the same user is again logged in. I want the account selection menu to pop up once again. What if the user wants to signin with other account?
Here's the signout code I'm using in Main2Activity:
HomeActivity/Main2Activity
findViewById(R.id.logoutButton).setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v)
{
firebaseAuth.signOut();
startActivity(new Intent(getApplicationContext(), LoginActivity.class));
finish();
}
});
}
LoginActivity/MainActivity
package com.dell.nfclib;
public class LoginActivity extends Activity
{
private static final int RC_SIGN_IN = 101;
GoogleSignInClient mGoogleSignInClient;
private FirebaseAuth mAuth;
SignInButton signInButton;
@Override
protected void onStart()
{
super.onStart();
}
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
// Configure Google Sign In
GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
.requestIdToken(getString(R.string.default_web_client_id))
.requestEmail()
.build();
// Build a GoogleSignInClient with the options specified by gso.
mGoogleSignInClient = GoogleSignIn.getClient(this, gso);
// Initialize Firebase Auth
mAuth = FirebaseAuth.getInstance();
signInButton = (SignInButton) findViewById(R.id.googleSignInButton);
signInButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
signIn();
}
});
}
private void signIn()
{
Intent signInIntent = mGoogleSignInClient.getSignInIntent();
startActivityForResult(signInIntent, RC_SIGN_IN);
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data)
{
super.onActivityResult(requestCode, resultCode, data);
// Result returned from launching the Intent from GoogleSignInApi.getSignInIntent(...);
if (requestCode == RC_SIGN_IN) {
GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);
if(result.isSuccess()) {
GoogleSignInAccount account = result.getSignInAccount();
firebaseAuthWithGoogle(account);
}
}
}
private void firebaseAuthWithGoogle(GoogleSignInAccount acct)
{
AuthCredential credential = GoogleAuthProvider.getCredential(acct.getIdToken(), null);
mAuth.signInWithCredential(credential)
.addOnCompleteListener(this, new OnCompleteListener<AuthResult>() {
@Override
public void onComplete(@NonNull Task<AuthResult> task) {
if (task.isSuccessful())
{
// Sign in success, update UI with the signed-in user's information
// Get user details from the 'user' object..
startActivity(new Intent(getApplicationContext(), HomeActivity.class));
finish();
}
else
{
// If sign in fails, display a message to the user.
Toast.makeText(getApplicationContext(), "Error", Toast.LENGTH_LONG).show();
}
// ...
}
});
}
}
Upvotes: 1
Views: 171
Reputation: 138979
But when I click on GoogleSignIn button again, the same user is again logged in.
This is happening because you haven't signed out completely.
I want the account selection menu to pop up once again.
To solve this, you need to sign-out from both, Firebase and Google accounts. A method like the following can help you solve your problem:
private void signOut() {
FirebaseFirestore.getInstance().signOut(); //Sign-out Firebase
if (googleApiClient.isConnected()) {
Auth.GoogleSignInApi.signOut(googleApiClient); //Sign-out Google
}
}
Upvotes: 1