CODEWITHSUNDEEP
pythondjangodjango-rest-framework
fat_potato
fat_potato

Reputation: 653

django not returning request response

i am using this code to make an api which return the post request so i can test and modify them according to my needs.

I have tried two codes by searching on SO. 

from django.http import HttpResponse, JsonResponse
from django.views.decorators.csrf import csrf_exempt
import json


@csrf_exempt
def some_view(request, username):
    json_data = json.dumps(request)
    return JsonResponse(json_data, safe=False)

This code give me the error of is not JSON serializable.

If i applied a list attribute to it. Like

from django.http import HttpResponse, JsonResponse
from django.views.decorators.csrf import csrf_exempt
import json


@csrf_exempt
def some_view(request, username):
    json_data = json.dumps(list(request))
    return HttpResponse(json_data)

it did not give me an error but return the empty output.[]

Edit: if i tried to return request.POST. I got a empty array.

I am testing this api through POSTMAN.

Upvotes: 0

Views: 2084

Answers (2)

Dhirendra
Dhirendra

Reputation: 790

If you want to read Request object attributes, you can use request.__dict__.
This will return you serailizable object something like

{
    'FILES': < MultiValueDict: {} > ,
    'COOKIES': {},
    '_post_parse_error': False,
    'resolver_match': None,
    'GET': < QueryDict: {} > ,
    'META': {},
    'path_info': u '',
    'path': u '',
    'POST': < QueryDict: {} > ,
    'method': None
}

You may need to iterate over and read __dict__ attributes of nested objects too, such as 'GET': <QueryDict: {}>, 'POST': <QueryDict: {}>.

Upvotes: 0

solarissmoke
solarissmoke

Reputation: 31494

request is a HttpRequest object - not the raw request body. You need to access that with request.body. You probably also want to use JsonResponse instead of HttpResponse if you want to return JSON via a Python object:

request_data = json.loads(request.body.decode('utf-8'))   # This assumes your request body is JSON
json_data = json.dumps(request_data)
return JsonResponse(json_data)

(I'm assuming that you will do a bit more that just returning the original request later on).

Upvotes: 2

Related Questions