Reputation: 463
I have to run an exe file through C# code and open the output file generated by the exe to do some pre-processing.
The output file is generated successfully by running the exe. But when I try to open the output file at the same run, I am getting File Not Found Exception but when I run the program again, the code reads my output file and I am able to do the pre-processing.
private static void launchExe()
{
string filename = Path.Combine("//myPathToExe");
string cParams = "argumentsToExe";
var proc = System.Diagnostics.Process.Start(filename, cParams);
proc.Close();
}
I now need to open the output file generated by the exe.
private static void openOutputFile()
{
StreamReader streamReader = new StreamReader("//PathToOutputFile");
string content = streamReader.ReadToEnd();
/*
* Pre Processing Code
*/
}
At this stage I am getting File Not Found Exception but I have the output file generated in the specified path.
Kindly help me with this issue.
Upvotes: 1
Views: 183
Reputation: 9491
Don't close your app, but WaitForExit.
string filename = Path.Combine("//myPathToExe");
string cParams = "argumentsToExe";
var proc = System.Diagnostics.Process.Start(filename, cParams);
proc.WaitForExit();
Upvotes: 4