CODEWITHSUNDEEP
hibernatespring-mvcgenericsspring-data-jpa
Kalana Weerarathne
Kalana Weerarathne

Reputation: 387

Is it possible to create common JpaRepository Interface?

I have created an interface like this,

@Repository
public interface IJpaRepositoryCustom<T> extends JpaRepository<T,Long>{
}

And service class

@Service
public class LOVService<T>{
    @Autowired
    private IJpaRepositoryCustom<T> jpaRepositoryCustom;
}

But with the above code, I am getting an exception

SEVERE [ContainerBackgroundProcessor[StandardEngine[Catalina]]] org.apache.catalina.core.StandardContext.listenerStart Exception sending context initialized event to listener instance of class [org.springframework.web.context.ContextLoaderListener] org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'IJpaRepositoryCustom': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Not a managed type: class java.lang.Object at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1699) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:573) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:495) at org.springframework.beans.factory.support.AbstractBeanFactory.lambda$doGetBean$0(AbstractBeanFactory.java:317)

Is there any other way to create a common JPA repository?

Thanks in advance.

Upvotes: 3

Views: 1842

Answers (2)

Angad Bansode
Angad Bansode

Reputation: 923

When we want to add custom methods into all Spring Data JPA repositories, the first thing that we have to is to create a base interface which declares the custom methods.

1) First Step:Create Base Interface

    //Annotation to exclude repository interfaces from being picked up and thus in consequence getting an instance being created.
@NoRepositoryBean  
public interface ReadOnlyRepository<T, ID extends Serializable> extends Repository<T, ID> {

    T findOne(ID id);

    List<T> findAll();

}

2) Second Step : Implementing the Base Repository Interface

public interface IUserReadOnlyRepository extends ReadOnlyRepository<User,Integer> 

{
    User findById(Integer id);

    List<User> findByName(String name);

    @Query("select u from MyUser u where u.name = ?1")
    List<User> findUserByAttributeAndValueCustomQuery(String string2);   
}

3) Third Step: Just Autowired into Controller/RESTController

  @RestController
    @RequestMapping("/user")
    @CrossOrigin
    //@EnableTransactionManagement
    public class UserController {

        @Autowired
        private IUserReadOnlyRepository userReadOnlyRepository;

    @RequestMapping(value = "/getUserByIdReadOnlyRepository/{id}")
    public @ResponseBody User getUserById(@PathVariable Integer id)
    { 
        User user = userReadOnlyRepository.findById(id);
        return user;

    }

Note: It is perfectly working for me!. If any help required, ping me.

Upvotes: 3

Pawan Tiwari
Pawan Tiwari

Reputation: 537

You can edit your service like this :

@Service
public class LOVService{

    @Autowired
    private IJpaRepositoryCustom jpaRepositoryCustom;
}

And your repo:

@Repository
public interface IJpaRepositoryCustom extends JpaRepository<YourEntityClass,Long>{
}

And there is no need to pass the argument to the repository if you're autowiring this.

I hope this will help.

Upvotes: 0

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