CODEWITHSUNDEEP
regexreplacepreg-replaceexpressionregular-language
Anthony
Anthony

Reputation: 3218

Replacement in regular expression

I have a list:

1  name1
2  name2
3  name3

I need to replace all 1,2,3... to '1', '2', '3'...and name1, name2, name3 to 'name1', 'name', 'name'3. I know how to do it via '\n' and '\s'.

But I think the better way exists. Does anybody know this way?

Upvotes: 1

Views: 569

Answers (3)

will
will

Reputation: 10650

you can do it easily with perl,

on a unix machine, from the terminal:

perl -pe 's/regex/replace/' input > output

(the > output is optional, and it will just get printed to the terminal)

so:

perl -pe "s/([0-9]+)\s(.*)/'\1' '\2'/g" file > file2

That will find at least one number at the beginning, and capture it (as \1). then some white space, then the rest of the line, captured (as \2). the after the / is the replace bit. just add in the ' s and insert the captured bits.

(if you're on windows, you can get perl here: http://www.perl.org/get.html#more)

Upvotes: 2

Atanas Korchev
Atanas Korchev

Reputation: 30671

Here is a JavaScript solution:

str = str.replace(/(\w+)/g, "'$1'");

Upvotes: 2

yoavmatchulsky
yoavmatchulsky

Reputation: 2960

Heres a little snippet in PHP:

$str = "1 name1\n2 name2\n3 name3";
$str2 = preg_replace('!([^\s]+)\s([^\n]+)!sm', "'$1' '$2'", $str);
echo $str2;

It uses $1 and $2 to reference the rounded bracket you 'catched' in the string

Upvotes: 1

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