CODEWITHSUNDEEP
javascript
Rohini S
Rohini S

Reputation: 13

validate regexp based on the variable after decimal point

var precision = !!values.amountprecision && values.amountprecision || '2';
var temp = /^\d+(\.\d{1,2})?$/;
temp.test(1.1221);

In the above expression, i have explicitly mentioned 1 to 2 values after decimal points. but i want to set the digits after decimal point should be based on the precision variable.

Upvotes: 0

Views: 53

Answers (2)

ChengWei
ChengWei

Reputation: 46

According your code 「var temp = /^\d+(.\d{1,2})?$/;」, I guess you need an integer or a float with 1 or 2 digits after the decimal point. And the number of digits determined by a variable, precision. If so, try this

let temp = new RegExp(`^\\d+(\\.\\d{${precision}})?$`);

Upvotes: 0

Amadan
Amadan

Reputation: 198324

Use the excplicit constructor instead of the literal:

var temp = new RegExp('^\d+(\.\d{' + precision + '})?$');

Upvotes: 1

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