CODEWITHSUNDEEP
pythoncurlpycurl
Mohammed
Mohammed

Reputation: 757

Equivalent python code for curl command for https call

I have a curl command that works and gives me back the JSON. Curl command:

    curl -sS -k -L -H "Authorization: bearer <token>" -X GET https://IP:PORT/api/v1/namespaces

I tried with requestsand pycurl modules which I found in the other posts but no luck.

Can anyone help me with finding the equivalent in python???

Upvotes: 0

Views: 447

Answers (1)

rje
rje

Reputation: 6418

We can do this with requests like this:

import requests
header = {'Authorization': 'bearer <token>'}
resp = requests.get("https://IP:PORT/api/v1/namespaces", 
    headers = header, 
    verify=False)
print(resp.status_code)
print(resp.text)
  • The -H switch behaviour is replicated by sending a header
  • The -L switch behaviour is replicated by specifying verify=False
  • The -sS and -k are about the behaviour of curl and not relevant here
  • The -X GET is replicated by using requests.get()

Upvotes: 1

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