Reputation: 152
After wasting a couple of days with this, I'm asking for help. I'm trying to specify Python 2.7 in setup.py:
from setuptools import setup, find_packages
setup(
name = 'MyPackageName',
version = '1.0.0',
url = 'https://github.com/mypackage.git',
author = 'Author Name',
author_email = '[email protected]',
description = 'Description of my package',
packages = find_packages(),
python_requires='>=2.7,!=3.0.*,!=3.1.*,!=3.2.*,!=3.3.*',
)
My pip version is 9.0.1 (in Python 27)
My setuptools verion is 38.4.0 (in Python 27)
I have 3 Pythons installed: 2.5, 2.7, 3.6
I'm building an exe with (Python 27):
python setup.py bdist_wininst
which creates nice MyPackageName-1.0.0.win32.exe
This is what I'm trying to achieve(numpy example with Py 2.5):
I would greatly appreciate any hints.
Upvotes: 1
Views: 832
Reputation: 66201
Use --target-version
to restrict the interpreter version:
$ python setup.py bdist_wininst --target-version 2.7
will build the installer MyPackageName-1.0.0.win32-py2.7.exe
. When installing, it will restrict the list of found versions to match the target one, or show an error dialog in there are none. Passing the option multiple times will generate multiple installers for each version, e.g.
$ python setup.py bdist_wininst --target-version 2.5 --target-version 2.7
will generate two installers, MyPackageName-1.0.0.win32-py2.5.exe
and MyPackageName-1.0.0.win32-py2.7.exe
.
Upvotes: 2