Reputation: 3086
Can PHP namespaces contain variables? If so, how can this be accomplished?
Upvotes: 77
Views: 46792
Reputation: 1354
Alternate ways that can make code more organized:
Instead of like \view\header\$links:
(1) Backslashes in array key for imaginary nesting, Example:
$myVar['view\header\links'] = 'value';
// OR use multidimentional arrays
$view['header']['links'] = 'value';
(1.1) Use Global Array, Example
// START - SETUP
define('I', 'mySite_19582730');
// END - SETUP
// Usage:
$GLOBALS[I]['view\header\links'] = 'value';
// OR
$GLOBALS[I]['view__header__links'] = 'value';
(1.1.1) Functions to get & set value in Global Array
function set($key, $val){
if (is_string($key)) $GLOBALS['site_8619403725'][$key] = $val;
elseif (is_array($key)){
foreach($key as $ky => &$vl) {
$GLOBALS['mySite_19582730'][$vl] = $val;
}
}
}
function get($key){
return @ $GLOBALS['mySite_19582730'][$key];
}
// Usage
set('view\header\search','<div></div>');
set(['view\header\logo','view\header\homeLink'], '<a href=""></a>');
get('view\header\search');
(2) Use __ (double underscores) in variable name to make imaginary nesting, Example:
$view__header__links = 'value';
Upvotes: 0
Reputation: 626
You can bound a variable to the namespace by wrapping the variable inside a function.
<?php
namespace furniture;
// instead of declaring a $version global variable, wrap it inside a function
function version(){
return "1.3.4";
}
?>
Upvotes: 3
Reputation: 960
It is not possible because $MYVARNAME
is still in the global scope. Try following code.
namespace.php
<?php
namespace MYNAME;
use MYNAME as M;
const MYVAR = 'MYVARNAME';
${M\MYVAR} = date('Y');
echo $MYVARNAME; // PRINT YEAR
$MYVARNAME = 'X';
echo $MYVARNAME; // PRINT X
echo ${M\MYVAR} ; // PRINT X
include('file.php');
?>
file.php
<?php
${MYNAME\MYVAR}=date('Y');
echo $MYVARNAME; // PRINT YEAR
$MYVARNAME = 'X';
echo $MYVARNAME; // PRINT X
echo ${MYNAME\MYVAR}; // PRINT X
include('file2.php');
?>
file2.php
<?php
namespace MYNAME2;
use MYNAME2 as N;
const MYVAR = 'MYVARNAME';
${N\MYVAR} = 'Y';
echo $MYVARNAME; // PRINT Y
echo ${MYNAME\MYVAR}; /* PRINT Fatal error: Uncaught Error:
Undefined constant 'MYNAME2\MYNAME\MYVAR' */
?>
Upvotes: 1
Reputation: 68
Store Complete classPath in Variable and use after 'new'.
It is very important to realize that because the backslash is used as an escape character within strings, it should always be doubled when used inside a string.
<?php
$a = "namespace\\className"; // 'which will print namespace/className'
$obj = new $a;
?>
Upvotes: 0
Reputation: 98
It can be done - sort of.
This is probably extremely bad and should never be done, but it is possible by using variable variables, and the magic constant for namespace. So a string-variable to name the variable we want to use, like so:
<?php
namespace your\namespace;
$varname = __NAMESPACE__.'\your_variablename'; //__NAMESPACE__ is a magic constant
$namespaced_variable = $$varname; //Note the double dollar, a variable variable
?>
Upvotes: 0
Reputation: 321
Try this
<?php
namespace App\login;
$p = 'login';
$test2 = '\App\\'.$p.'\\MyClass';
$test = new $test2;
Upvotes: 28
Reputation: 24730
No they cannot, as mario said.
To encapsulate variables use Classes. Polluting the global variable space should definitely be avoided.
Example
class_dbworker.php:
class DbWorker
{
//properties and method logic
}
class DbWorkerData
{
public static $hugerelationsmap = array(....);
public static ....
}
mainapp.php:
include_once 'class_dbworker.php';
print_r( DbWorkerData::$hugerelationsmap );
Example using namespaces
class_dbworker.php:
namespace staticdata;
class DbWorker
{
//properties and method logic
}
class DbWorkerData
{
public static $hugerelationsmap = array(....);
public static ....
}
mainapp.php:
include_once 'class_dbworker.php';
use staticdata as data;
print_r( \data\DbWorkerData::$hugerelationsmap );
Upvotes: 18
Reputation: 145482
No. You can set a variable after declaring a namespace, but variables will always exist in the global scope. They are never bound to namespaces. You can deduce that from the absence of any name resolution descriptions in
There would also be no allowed syntax to locate variables in a namespace.
print \namespace\$var; // syntax error
print "${namespace\\var}"; // "unexpected T_NS_SEPARATOR"
Upvotes: 60