CODEWITHSUNDEEP
c++
Mohammadjavad Kariminia
Mohammadjavad Kariminia

Reputation: 21

Floating point exception (core dumped) #694457

I don't know C++ well, and I don't understand why but this error occurred: Floating point exception (core dumped)

I don't know how can I fix it.

#include <iostream>

using namespace std;

int main() {

    int a = 251;
    int b = 0;

    while (a > 0) {
        a = a / 10;
        b++;
    }
    int c = 2;
    int d = 1;
    while (c <= b) {
        d = d * 10;
        c++;
    }
    cout << d;
    int answer = 0;
    int f = d;
    int g = 1;
    float help;
    while (b > 0) {
        help = (a / (d * g)) *(d / f);
        answer = answer + (int)help;
        a = a % (d * g);
        g = g * (1 / 10);
        f = f * (1 / 10);
        b--;
    }

    cout << answer;

    return 0;
}

Upvotes: 1

Views: 3384

Answers (3)

Abhay Raj Singh Rathod
Abhay Raj Singh Rathod

Reputation: 26

As answered here

Better use:

g = g/10;
f = f/10;

for integral values. Also check for g and f not equal to zero before dividing.

I hope this helps ;)

Upvotes: 0

pptaszni
pptaszni

Reputation: 8228

Whenever you have "core dumped" you can use GDB to investigate your crash: gdb binary core. Here is what happens in your code:

Program terminated with signal SIGFPE, Arithmetic exception.
#0  (...)
    at (...):LINE_NUM
LINE_NUM             help = (a /(d * g)) *(d /f);

During second iteration your f and g are already equal to 0. In Linux you can catch SIGFPE signal and handle the error, or you can check the variables in your code before performing a division.

Upvotes: 0

Lightness Races in Orbit
Lightness Races in Orbit

Reputation: 385194

Counter-intuitively, a "floating-point exception" is an exception kicked out by your CPU and/or Operating System when you attempt to perform integer division by zero.

C++ makes this operation undefined; your computer outright prohibits it.

Check all your variables when you step through your program with your debugger, and remember that 1 / 10 is zero, not 0.1, because it's integer division. (This mistake propagates to the next iteration of your loop, where you attempt to use this zero value as a divisor.)

Dividing a floating-point number by zero is more well-defined and ISTR it will kick out the special value inf.

Upvotes: 1

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