CODEWITHSUNDEEP
pythonpandascompare
Harinie R
Harinie R

Reputation: 307

python pandas - get matching and non matching records between two dataframes

I'm new to use pandas in python whereas I have good knowledge in working with python.

I've two data frames from which I've to get matching records and non matching records into new data frames.

Example :

DF1 :

ID Name Number    DOB     Salary
1  AAA  1234   12-05-1996 100000
2  BBB  1235   16-08-1997 200000
3  CCC  1236   24-04-1998 389999
4  DDD  1237   05-09-2000 450000

DF2 :

ID Name Number    DOB     Salary
1  AAA  1234   12-05-1996 100000
2  BBB  1235   16-08-1997 200000
3  CCC  1236   24-04-1998 389999
4  DDD  1237   05-09-2000 540000

And, with primary keys being ID & Name here(in reality the number of keys might vary), I need to get

Match_df :

ID Name Number    DOB     Salary
1  AAA  1234   12-05-1996 100000
2  BBB  1235   16-08-1997 200000
3  CCC  1236   24-04-1998 389999

Mismatch_df :

ID Name Number    DOB     Salary
4  DDD  1237   05-09-2000 540000

I've tried all possible ways like

pd.merge(df1, df2, left_on=[ID,Name],right_on=[ID,Name], how='inner')

and this produces all the unique keys that are in both the data frames. But this also produces non matching records.

But I'm getting this as my result :

ID Name Number    DOB     Salary
1  AAA  1234   12-05-1996 100000
2  BBB  1235   16-08-1997 200000
3  CCC  1236   24-04-1998 389999
4  DDD  1237   05-09-2000 540000

where 4th record is also getting included.

Here, only salary col is varying but in real Time, it may be a list of cols to be compared.

From this, I've to get only matching records to the matched_df and non matching records to the mismatch_df.

Kindly help me out in doing this.

Note: My dataset might be a massive one (100 million records in both datasets) so, please get me an effective approach reducing the time of execution.

Thanks in advance.

Upvotes: 6

Views: 25090

Answers (4)

b2002
b2002

Reputation: 914

# pick index keys and compare column(s)
keys = ['ID', 'Name']
# if comparing all columns:
col_list = [col for col in df1.columns if col not in keys]
# # if comparing specific columns:
# col_list = ['Salary', 'DOB']

# extend keys with col_list for next step
sel_cols = keys.copy()
sel_cols.extend(col_list)

# set a multi-index with keys
# to dataframes with col_list columns
dfa = df1[sel_cols].set_index(keys)
dfb = df2[sel_cols].set_index(keys)

# make an equivalency boolean mask
dfa.update(dfb)
mask = np.equal(df1[col_list].values, dfa.values).all(axis=1)

# slice df1 with mask
Match_df = df1[mask]
Mismatch_df = df1[~mask]

Upvotes: 5

Karn Kumar
Karn Kumar

Reputation: 8826

Simplistic Answer to your question is with df1.where :

Note: The resulting cells with NaN do not satisfy the conditions, i.e. they are not equal in the two dataframes. The ones that have a real value are the ones that are equal in the two dataframes

>>> df1.where(df1.Salary==df2.Salary)
          DoB   ID  Name    Salary
0  12-05-1996  1    AAA  100000.0
1  16-08-1997  2    BBB  200000.0
2  24-04-1998  3    CCC  389999.0
3         NaN  NaN  NaN       NaN

While going with pd.merge: If you Just want to merge the df1 & df1 without Column or index level then it will take defaults to the intersection of the columns in both DataFrames.

>>> pd.merge(df1, df2)
          DoB  ID Name  Salary
0  12-05-1996   1  AAA  100000
1  16-08-1997   2  BBB  200000
2  24-04-1998   3  CCC  389999

If you wish to Join Column or index level then use on. 

 >>> pd.merge(df1, df2, on="Salary")
        DoB_x  ID_x Name_x  Salary       DoB_y  ID_y Name_y
0  12-05-1996     1    AAA  100000  12-05-1996     1    AAA
1  16-08-1997     2    BBB  200000  16-08-1997     2    BBB
2  24-04-1998     3    CCC  389999  24-04-1998     3    CCC

For mismatch in df2: you can opt isin(dict) method:

>>> df2[~df2.isin(df1.to_dict('l')).all(1)]
          DoB  ID Name  Salary
3  05-09-2000   4  DDD  540000

another way as Mabel given.

df2[~df2.isin(df1).all(axis=1)]

Upvotes: 7

Mabel Villalba
Mabel Villalba

Reputation: 2598

To get the match:

>> df1.merge(df2)

ID Name  Number         DOB  Salary
0   1  AAA    1234  12-05-1996  100000
1   2  BBB    1235  16-08-1997  200000
2   3  CCC    1236  24-04-1998  389999

And for the mismatch selecting the row in df2:

>> df2[~df2.isin(df1).all(axis=1)]

   Name  Number         DOB  Salary
ID                                 
4   DDD    1237  05-09-2000  540000

Upvotes: 0

Alexis Drakopoulos
Alexis Drakopoulos

Reputation: 1145

My solution would be a bit different and would involve simply copying the salary from the other dataset over.

Such as:

DF1["Salary2"] = DF2["Salary"]

MatchDF = DF1[DF1["Salary"] == DF1["Salary2"]]
MisMatchDF = DF1[DF1["Salary"] != DF1["Salary2"]]

Upvotes: 0

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