Reputation: 810
I have this SQL query that I need to convert to CakePHP. I used this website [http://dogmatic69.com/sql-to-cakephp-find-converter][1] that converts the code but I doesn't work in the way that I want. There is no results.
I think it is because it creates an empty array here is the SQL code :
SELECT shops.phone1 FROM galleries , albums , shops
WHERE galleries.album_id = albums.id and albums.shop_id = shops.id and galleries.id = 210
and this is the result the website gives me :
$options = array(
'fields' => array(
'shops.phone1',
),
'joins' => array(
array(
),
),
'conditions' => array(
'Gallery.album_id = albums.id',
'albums.shop_id = shops.id',
'Gallery.id' => '210',
),
);
$data = $this->find('all', $options);
but the code doesn't work.
Any Ideas what could be wrong ?
Thanks
Upvotes: 0
Views: 263
Reputation: 5682
There are many ways to achieve this. If you have defined your associations correctly then you can do this:
$data = $this->Shops->find('all')
->contain(['Galleries','Albums'])
->fields(['Shops.phone1'])
->where(['Galleries.id' => 210]);
Otherwise you can use custom join to generate your query:
$data = $this->Shops->find('all')
->join([
'albums' => [
'table' => 'albums',
'type' => 'INNER', // define your join type here
'conditions' => 'albums.shop_id = Shops.id',
],
'galleries' => [
'table' => 'galleries',
'type' => 'INNER', // define your join type here
'conditions' => 'galleries.album_id=albums.id',
]
])
->select(['Shops.phone1'])
->where(['galleries.id' => 210]);
Further Reading: Cakephp -> Query Builder -> Adding Joins
Upvotes: 1