CODEWITHSUNDEEP
pythonsqlsqlalchemy
NotSoShabby
NotSoShabby

Reputation: 3698

making alias for case statement in the where clause - SQLalchemy

I need to create a calculated column in my SQL query using SQLAlchemy. The query i would like to get will look like this:

SELECT *, CASE WHEN (age < 18) THEN 1 ELSE 0 END AS kid 
FROM (SELECT TEST_TABLE.index AS index, TEST_TABLE.age AS age, TEST_TABLE.letter AS letter 
FROM TEST_TABLE) AS dataset

Now, I managed to do so with SQLAlchemy like this:

query = select(['*', case([(Column('age').op('<')(18), 1)], else_=0)])
query.select_from(alias(select([*]), name='dataset'))   # I actually pass different params here, but this is an example

But I didn't manage to put another alias() function to make the calculated column that i added be called "kid" like I want. SQLAlchemy generates its own alias for it instead.

I tried:

query = select(['*', case([(alias(Column('age').op('<')(18), name='kid'), 1)], else_=0)])

and:

query = select(['*', alias(case([(Column('age').op('<')(18), 1)], else_=0), name='kid')])

No success there. Any ideas?

Upvotes: 0

Views: 1571

Answers (1)

Nebi
Nebi

Reputation: 326

Like I said in the comment I'm not familiar with sqlalchemy. But maybe this will help you:

query = select(['*', case([(Column('age').op('<')(18), 1)], else_=0).label("kid")])
query.select_from(alias(select([*]), name='dataset'))

But I'm really not sure if the syntax is right here. Maybe also look here: Using alias() for 'select as' in SQLAlchemy

Upvotes: 1

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