CODEWITHSUNDEEP
pythonnumpy
chaos
chaos

Reputation: 133

How is the data of a numpy.array stored?

This is my simple test code:

data = np.arange(12, dtype='int32').reshape(2,2,3);

so the data is:

array([[[ 0,  1,  2],
    [ 3,  4,  5]],

   [[ 6,  7,  8],
    [ 9, 10, 11]]], dtype=int32)

but why does data.data[:48] look like this:

'\x00\x00\x00\x00\x01\x00\x00\x00\x02\x00\x00\x00\x03\x00\x00\x00\x04\x00\x00\x00\x05\x00\x00\x00\x06\x00\x00\x00\x07\x00\x00\x00\x08\x00\x00\x00\t\x00\x00\x00\n\x00\x00\x00\x0b\x00\x00\x00'

I mean why are '9','10' stored as '\t\x00\x00\x00' and '\n\x00\x00\x00'?

Upvotes: 2

Views: 55

Answers (1)

Amadan
Amadan

Reputation: 198526

\t is the tab character, of ASCII value 9. \n is the LF character, of ASCII value 10. \x00 is a NUL character, of ascii value 0. Thus,

'\t\x00\x00\x00' represents a sequence of bytes [9, 0, 0, 0], which is a little-endian representation of a long integer 9.

'\n\x00\x00\x00' represents a sequence of bytes [10, 0, 0, 0], which is a little-endian representation of a long integer 10.

Upvotes: 3

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