Reputation: 1
I'm trying write a query to find records which don't have a matching record in another table.
For example, I have a two tables whose structures looks something like this:
Table1
Address ID | Address Type
AD7233654242 | Condo
AD7233654242 | Condo
AD7233654243 | Apartment
AD7233654244 | Condo
Table2
Address ID | Address Type
AD7233654242 | Condo
AD7233654242 | Apartment
AD7233654243 | Apartment
AD7233654244 | Condo
Based on the data from above you'll notice address ID AD7233654242 has a mismatch Address Type. Table A shows Condo and Table B shows Apartment. So in the query result I want to dislay the Address ID and Address Type from both of the tables.
Any suggestions on a query to do this?
Upvotes: 0
Views: 64
Reputation: 9460
You can query matching and not matching records using join
type. Below are examples of different joins.
declare @tbl1 table(AddressID varchar(20), AddressType varchar(50))
declare @tbl2 table(AddressID varchar(20), AddressType varchar(50))
insert @tbl1(AddressID,AddressType) values
('AD7233654242', 'Condo'),
('AD7233654242', 'Condo'),
('AD7233654243', 'Apartment'),
('AD7233654244', 'Condo'),
('AD7233654245', 'Condo')--my sample
insert @tbl2(AddressID,AddressType) values
('AD7233654242', 'Condo'),
('AD7233654242', 'Apartment'),
('AD7233654243', 'Apartment'),
('AD7233654244', 'Condo')
--records in @tbl1 matching @tbl2
select t1.AddressID addrId_1, t1.AddressType addrType_1, t2.AddressID addrId_2, t2.AddressType addrType_2
from @tbl1 t1 -- 1st or left table
inner join @tbl2 t2 --2nd or right table
on t1.AddressID=t2.AddressID and t1.AddressType=t2.AddressType
--records in @tbl1 not matching @tbl2
select t1.AddressID, t1.AddressType
from @tbl1 t1
left join @tbl2 t2 on t1.AddressID=t2.AddressID and t1.AddressType=t2.AddressType
where t2.AddressID is null
--records in @tbl2 not matching @tbl1
select t2.AddressID, t2.AddressType
from @tbl1 t1
right join @tbl2 t2 on t1.AddressID=t2.AddressID and t1.AddressType=t2.AddressType
where t1.AddressID is null
--all mismatches
select t1.AddressID addrId_1, t1.AddressType addrType_1, t2.AddressID addrId_2, t2.AddressType addrType_2
from @tbl1 t1
full join @tbl2 t2 on t1.AddressID=t2.AddressID and t1.AddressType=t2.AddressType
where t1.AddressID is null or t2.AddressID is null
Upvotes: 1
Reputation: 743
I guess this is what you are asking..
SELECT * from table1 T1
where exists (
SELECT * from table2 T2
where T1.AddressID = T2.AddressID
and T1.AddressType<>T1.AddressType)
UNION
SELECT * from table1 T2
where exists (
SELECT * from table2 T1
where T1.AddressID = T2.AddressID
and T1.AddressType<>T1.AddressType)
Upvotes: 0
Reputation: 37473
You can try using left join and null in where condition
SELECT t1.AddressID, t1.AddressType,t2.AddressType
FROM Table1 t1
left JOIN Table2 t2
ON t1.AddressID = t2.AddressID AND t1.AddressType=t2.AddressType
where t2.AddressID is null
Upvotes: 0
Reputation: 521249
A simple join should work here:
SELECT
t1.AddressID,
t1.AddressType,
t2.AddressType
FROM Table1 t1
INNER JOIN Table2 t2
ON t1.AddressID = t2.AddressID AND t1.AddressType <> t2.AddressType;
This would actually return two records for AD7233654242
. If you have a certain expected output, we can modify the above query using that logic.
Upvotes: 0