CODEWITHSUNDEEP
c#regexstringreplace
Piotr
Piotr

Reputation: 65

Regex - replacing chars in C# string in specific cases

I want to replace all brackets to another in my input string only when between them there aren't digits. I wrote this working sample of code:

    string pattern = @"(\{[^0-9]*?\})";
                MatchCollection matches = Regex.Matches(inputString, pattern);
                if(matches != null)
                {
                    foreach (var match in matches)
                    {
                        string outdateMatch = match.ToString();
                        string updateMatch = outdateMatch.Replace('{', '[').Replace('}', ']');
                        inputString = inputString.Replace(outdateMatch, updateMatch);
                    }
                }

So for:

string inputString = "{0}/{something}/{1}/{other}/something"

The result will be:

inputString = "{0}/[something]/{1}/[other]/something"

Is there possibility to do this in one line using Regex.Replace() method?

Upvotes: 2

Views: 128

Answers (3)

Vegarbass
Vegarbass

Reputation: 1

Could you do this?

Regex.Replace(inputString, @"\{([^0-9]*)\}", "[$1]");

That is, capture the "number"-part, then just return the string with the braces replaced.

Not sure if this is exactly what you are after, but it seems to fit the question :)

Upvotes: 0

jlew
jlew

Reputation: 10591

Regex.Replace(input, @"\{0}/\{(.+)\}/\{1\}/\{(.+)}/(.+)", "{0}/[$1]/{1}/[$2]/$3")

Upvotes: 0

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626689

You may use

var output = Regex.Replace(input, @"\{([^0-9{}]*)}", "[$1]");

See the regex demo.

Details

  • \{ - a { char
  • ([^0-9{}]*) - Capturing group 1: 0 or more chars other than digits, { and }
  • } - a } char.

The replacement is [$1], the contents of Group 1 enclosed with square brackets.

Upvotes: 2

Related Questions