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javascriptarraysfilternumbers
N. Levenets
N. Levenets

Reputation: 87

JavaScript: Check if an array element is a number

I have an array of arbitrary elements and need to get only number elements. I tried arr.filter((c) => !isNaN(parseInt(arr[c]))); but that didn't work. I still have a full array. What is wrong here and what else can I do?

Upvotes: 3

Views: 17225

Answers (2)

Ele
Ele

Reputation: 33726

You're trying to access an index using the numbers, change to this:

let newArray = arr.filter((c) => !isNaN(parseInt(c)));
                                                 ^

Further, you need to use the array which is returned by the function filter.

Upvotes: 1

CertainPerformance
CertainPerformance

Reputation: 370759

The first argument in the callback to .filter is the array item being iterated over - if c is the array item, then referencing arr[c] usually doesn't make much sense. Try using a simple typeof check instead:

const arr = [3, 'foo', { bar: 'baz' }, false, 4, 5];
console.log(arr.filter(item => typeof item === 'number'));

Upvotes: 7

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