Reputation: 4638
I am trying to find difference between two dataframe and the resulting df should return the rows matching the first dataframe. Since id's 6,7 was not there in df2 so the count value is as it is.
My Two Dataframes
Resulting Dataframe:
Upvotes: 0
Views: 1038
Reputation: 863611
Use sub
with set_index
for align DataFrame
s by id
columns, add reindex
for id
only by df1.id
:
df = (df1.set_index('id')
.sub(df2.set_index('id'), fill_value=0)
.reindex(df1['id'])
.astype(int)
.reset_index())
print (df)
id count
0 1 0
1 2 0
2 3 0
3 4 0
4 5 0
5 6 9
6 7 4
Another solution with merge
and left join, then subtract by sub
with extracting count_
column by pop
:
df = df1.merge(df2, on='id', how='left', suffixes=('','_'))
df['count'] = df['count'].sub(df.pop('count_'), fill_value=0).astype(int)
print (df)
id count
0 1 0
1 2 0
2 3 0
3 4 0
4 5 0
5 6 9
6 7 4
Setup:
df1 = pd.DataFrame({'id':[1,2,3,4,5,6,7],
'count':[3,5,6,7,2,9,4]})
print (df1)
id count
0 1 3
1 2 5
2 3 6
3 4 7
4 5 2
5 6 9
6 7 4
df2 = pd.DataFrame({'id':[1,2,3,4,5,8,9],
'count':[3,5,6,7,2,4,2]})
print (df2)
id count
0 1 3
1 2 5
2 3 6
3 4 7
4 5 2
5 8 4
6 9 2
Upvotes: 3
Reputation: 9081
Use:
temp = pd.merge(df1, df2, how='left', on='id').fillna(0)
temp['count'] = temp['count_x'] - temp['count_y']
temp[['id', 'count']]
id count
0 1 0.0
1 2 0.0
2 3 0.0
3 4 0.0
4 5 0.0
5 6 9.0
6 7 4.0
Upvotes: 0