CODEWITHSUNDEEP
jsonswift
Israel
Israel

Reputation: 121

sort and list JSON array by property in swift

I have the following json array

[
  {
    "name" : "v1",
    "available" : 1
  },
  {
    "name" : "v2",
    "available" : 3
  },
  {
    "name" : "v3",
    "available" : 2
  },
  {
    "name" : "v4",
    "available" : 3
  },
  {
    "name" : "v5",
    "available" : 3
  },
  {
    "name" : "v6",
    "available" : 1
  },
  {
    "name" : "v7",
    "available" : 2
  }
]

the available show some numbers which means: 1 and 3 is ok 2 is not ok

How can I order that json array by available value, showing first the 1 and 3 values and the last the value with 2. The result list should looks like this:

[
  {
    "name" : "v1",
    "available" : 1
  },
  {
    "name" : "v6",
    "available" : 1
  },
  {
    "name" : "v2",
    "available" : 3
  },
  {
    "name" : "v4",
    "available" : 3
  },
  {
    "name" : "v5",
    "available" : 3
  },
  {
    "name" : "v3",
    "available" : 2
  },
  {
    "name" : "v7",
    "available" : 2
  }
]

How can I do that?

Note: I use swiftyJson

This is my code:

sortArrayOddsBeforeEvens(array: json_array)

func sortArrayOddsBeforeEvens(array: JSON){
  let odds = array.filter{ $0.1["available"].intValue % 2 != 0 }
  let evens = array.filter{ $0.1["available"].intValue % 2 == 0 }
  print(odds)
  print(evens)
}

How can I return that as JSON?

Upvotes: 0

Views: 209

Answers (2)

Ryan
Ryan

Reputation: 4884

var array: [Int] = [1, 3, 2, 2, 1, 3, 3, 1, 2, 1, 3, 2, 2, 1]
array.filter({ return $0 != 2 }) + array.filter({ return $0 == 2})

Basically the logic is same.

let data = """
[
{ "name" : "v1", "available" : 1 },
{ "name" : "v2", "available" : 3 },
{ "name" : "v3", "available" : 2 },
{ "name" : "v4", "available" : 3 },
{ "name" : "v5", "available" : 3 },
{ "name" : "v6", "available" : 1 },
{ "name" : "v7", "available" : 2 }]
""".data(using: .utf8)!

let array = JSON(data).arrayValue
let result = array.filter({ return $0["available"].intValue != 2}) + array.filter({ return $0["available"].intValue == 2})

Upvotes: 0

vadian
vadian

Reputation: 285082

You are going to sort the array by two criteria.

Suggestion aka usual algorithm: First sort by odd/even, if both values are equal sort by the integer value.

let array = [["name" : "v1", "available" : 1],["name" : "v6", "available" : 1],["name" : "v2", "available" : 3],["name" : "v4", "available" : 3],["name" : "v5", "available" : 3],["name" : "v3", "available" : 2],["name" : "v7", "available" : 2]]

let sortedArray = array.sorted { (d1, d2) -> Bool in
    let avail1 = d1["available"] as! Int
    let avail2 = d2["available"] as! Int
    let compareOddity = avail1 % 2 == 0 && avail2 % 2 != 0
    if compareOddity { return !compareOddity }
    return avail1 < avail2
}

print(sortedArray)

Two avoid ugly boilerplate code drop SwiftyJSON and use Decodable to decode the JSON into structs.
The code will look much cleaner (and is more efficient)

let sortedArray = array.sorted { (d1, d2) -> Bool in
    let compareOddity = d1.available % 2 == 0 && d2.available % 2 != 0
    if compareOddity { return !compareOddity }
    return d1.available < d2.available
}

Upvotes: 1

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