Reputation: 107
I have a vector containing a bunch of file paths, like this:
v <- paste0("D:\\file\\path", 1:3)
I want to replace all the double backslashes with just a single backslash. So the output would look like this:
"D:\file\path1" "D:\file\path2" "D:\file\path3"
I tried this:
sapply(df, cat)
However this just generates a list of NULL values. I also tried:
for (i in 1:length(v)) {
v[i] <- cat(v[i])
}
But this gives an error: replacement has zero lengths. I'm not sure what I'm doing wrong.
Upvotes: 1
Views: 1193
Reputation: 166
The \
is an escape character in R, thus replacing \\
by \
will cause wrong interpretation from R.
If the need is for paths, use the /
character instead of \\
:
v <- gsub(v, pattern="\\", replacement="/", fixed=TRUE)
Upvotes: 3