CODEWITHSUNDEEP
pythonpython-3.xlistdictionarydata-structures
user10227621
user10227621

Reputation:

How to replace characters in list item as keys with values in dictionary

I'm trying to do something like this:

My input: 

predefined_list=['gross pay']
predefined_dict={'a':'o','o':'a','g':'c','c':'g'}

Desired 

output: ['gross pay', 'gross poy', 'grass pay', 'crass pay', cross pay, crass poy]

and other several combinations.

i tried:

predefined_list=['gross pay']
predefined_dict={'a':'o','o':'a','g':'c','c':'g'}

i=0;
for key,value in predefined_dict.items():
    final=predefined_list[i].replace(key,value)
    i+=1
    if final not in predefined_list:
        predefined_list.append(final)
print(predefined_list)

Upvotes: 0

Views: 73

Answers (2)

Davo
Davo

Reputation: 566

Try this way

for key, value in predefined_dict.items():
        for  word in predefined_list:
            for n in range(word.count(key)):
                final = word.replace(key,value,n+1)
                if final not in predefined_list:
                    predefined_list.append(final)

Output:

>>> predefined_list

['gross pay', 'gross poy', 'grass pay', 'grass poy', 'cross pay', 'cross poy', 'crass pay', 'crass poy']

Upvotes: 0

J. Doe
J. Doe

Reputation: 3634

Just replace your string by iterating through your dictionary's keys and values 

modified_list = [predefined_list[0].replace(k,v) for k,v in predefined_dict.items()]

Output

['gross poy', 'grass pay', 'cross pay', 'gross pay']

Similarly

predefined_list = ['pay gross', 'gross pay']
modified_dict = {list_k: [list_k.replace(k,v) for k,v in predefined_dict.items()]
                 for list_k in predefined_list}

Output 

{'gross pay': ['gross poy', 'grass pay', 'cross pay', 'gross pay'],
 'pay gross': ['poy gross', 'pay grass', 'pay cross', 'pay gross']}

Upvotes: 1

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