CODEWITHSUNDEEP
arraysbashfor-loop
bluethundr
bluethundr

Reputation: 1325

Replace Newline With Space In Array Element In a For Loop In Bash

I'm assigning values to an array inside a for loop:

aws_user_roles+=("$aws_role_name")

If I were assigning the values of the array from a command and want to strip the newline I could go: 

 readarray -t aws_roles < <(...some aws commands...)

My for loop looks something like this:

for ((has_role_index=0;has_role_index<${#aws_user_has_roles[@]};++has_role_index)); do         
             aws_user_roles+=("$aws_role_name")
             declare -p aws_user_roles
done

How can I strip out the newline from the array elements in aws_user_roles and replace it with a space?

Upvotes: 0

Views: 1445

Answers (2)

oguz ismail
oguz ismail

Reputation: 50750

Use pattern substitution:

aws_user_roles+=("${aws_role_name//$'\n'/ }")

From man bash:

${parameter/pattern/string}

Pattern substitution. The pattern is expanded to produce a pattern just as in pathname expansion. Parameter is expanded and the longest match of pattern against its value is replaced with string. If pattern begins with /, all matches of pattern are replaced with string. Normally only the first match is replaced

Upvotes: 1

KamilCuk
KamilCuk

Reputation: 140990

Use tr:

aws_user_roles+=("$(<<<"$aws_role_name" tr '\n' ' ')")
  • $(..) is command substitution
  • <<<"$variable" is a here-string
  • tr '\n' ' ' substitutes newlines for spaces.

Upvotes: 3

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