CODEWITHSUNDEEP
python
user968000
user968000

Reputation: 1843

How can I pack a string in struct.pack

I am trying to pack a string using struct.pack. I am able to see complete value if I use integer type but when I want to use string I only see one character.

struct.pack("<1L",0xabcdabcd)
'\xab\xcd\ab\cd'
struct.pack("<1s","overflow")
'o' prints just s. I wanted it to print full string: overflow.

Upvotes: 0

Views: 712

Answers (1)

Harry Cutts
Harry Cutts

Reputation: 1414

In the format string ("<1s") you're passing to struct.pack, the 1 denotes the maximum number of characters that field can store. (See the paragraph beginning "For the 's'..." in the struct documentation.) Since you're passing 1, it will only store the first character. You'll need to choose a length that will fit any string you want to store in the struct, and specify that. For example, to store the string "overflow" (8 characters) you could use "<8s":

>>> struct.pack("<8s", "overflow")
'overflow'

Upvotes: 2

Related Questions