CODEWITHSUNDEEP
c
Jonathan
Jonathan

Reputation: 53

Warning makes integer from pointer without a cast

expected ‘int’ but argument is of type ‘char *’ dont know how to correct, any suggestion

#include <stdio.h>

int my_strncmp(char const *s1, char const *s2, int n);

int main (int ac, char **ag) {
    char result;

    if (ac == 4) {
        result = my_strncmp(ag[1], ag[2], ag[3]);
        printf("%d\n", result);
    }   
    return(0);
}

Upvotes: 0

Views: 621

Answers (3)

Gimantha Dissanayake
Gimantha Dissanayake

Reputation: 9

in here,

int my_strncmp(char const *s1, char const *s2, int n);

the last part is int n

result = my_strncmp(ag[1], ag[2], ag[3]);

but here what you are passing ag[3] is of type char

hope this helps..

Upvotes: 0

DevSolar
DevSolar

Reputation: 70223

You need to convert ag[3] (of type char * / string) to an integer.

Have a look at strtol() and its brethren. With atoi() exists a simpler function, which however is not as robust and versatile. That is why I would recommend getting into the habit of using strtol() et al., always.

Sidenote, "n" parameters are usually made size_t (unsigned) instead of int. (Compare strncmp()). You'd use strtoul() then.

Upvotes: 3

newbie
newbie

Reputation: 608

The last parameter of my_strncmp is defined as an int n, yet when it is called in main the third parameter is char * type

Upvotes: 0

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