CODEWITHSUNDEEP
ruby-on-railsruby-on-rails-5
DollarChills
DollarChills

Reputation: 1086

Get first item in each_with_index result

I have a loop that collects all items with index value of 0 via has_many through scenario.

<% @trial.treatment_selections.each do |t| %>
    <% t.establishment_methods.each_with_index do |e, index| %>
        <% if index == 0 %>
            <%= index %> | <%= e.assessment_date %><br />
        <% end %>
    <% end %>
<% end %>

This out puts 4 dates of the same value all with the same index of 0. ie.

0 | 2018-12-31
0 | 2018-12-31
0 | 2018-12-31
0 | 2018-12-31

My questions is, is there a way to grab only to first item in the loop? e.assessment_date.first, e.assessment_date[0] don't seem to be viable options.

Upvotes: 0

Views: 115

Answers (1)

EmmanuelB
EmmanuelB

Reputation: 1427

You can achieve it in different ways. Following your cycle idea, you could use each_with_index in your first loop as well:

<% @trial.treatment_selections.each_with_index do |t, outer_index| %>
    <% t.establishment_methods.each_with_index do |e, inner_index| %>
        <% if outer_index == 0 && inner_index == 0 %>
            <%= inner_index %> | <%= e.assessment_date %><br />
        <% end %>
    <% end %>
<% end %>

But the best way to do it is in just one line

0 | <%= @trial.treatment_selections.first&.establishment_methods.first&.assessment_date %>

The index will always be 0 when you want to print it.

Upvotes: 1

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