Reputation: 112
Expected result is 3201:20. I have done this with split with ":". Please suggested best way to achieve this.
DECLARE @tmpTime TABLE
(
RowId INT IDENTITY(1, 1),
EmployeeId INT,
TotalWorkingTime NVARCHAR(10)
);
INSERT INTO @tmpTime
(
EmployeeId, TotalWorkingTime
)
VALUES
(1,N'1500:30'),
(2,N'1700:50');
SELECT SUM(TotalWorkingTime) FROM @tmpTime
Upvotes: 0
Views: 601
Reputation: 2341
As you can see from @GordonLinoff's answer, your query is quite complex when using a VARCHAR
to represent what is really a duration of time. If you represent your data in a more natural way, your query becomes much simpler. For example, if you store your time worked as an integer (total minutes), you can use an intermediate CTE and a couple of CROSS APPLY
s to get what you need:
-- note that TotalWorkingTime is now TotalWorkingTimeMinutes
DECLARE @tmpTime TABLE
(
RowID INT IDENTITY(1,1),
EmployeeID INT,
TotalWorkingTimeMinutes INT
);
-- while I'm using a calculation to show
-- how the minutes get added, this would likely
-- be done by the application, before it gets
-- sent to the database.
INSERT INTO @tmpTime
(EmployeeID, TotalWorkingTimeMinutes)
VALUES
(1, (1500 * 60) + 30),
(2, (1700 * 60) + 50);
-- I think this intermediate CTE makes things a bit clearer.
-- but of course, you can inline it as well.
WITH SummedMinutesWorked(SummedMinutes) AS
(
SELECT SUM(TotalWorkingTimeMinutes)
FROM @tmpTime
)
-- you can use the CROSS APPLY to get the hours,
-- then reference those to get the "remainder minutes"
-- the SELECT has to cast your hours and minutes to a VARCHAR
-- for concatenation
SELECT CAST(H AS VARCHAR(255)) + ':' + CAST(M AS VARCHAR(255))
FROM SummedMinutesWorked
CROSS APPLY (SELECT SummedMinutes / 60 AS H) AS HoursWorked
CROSS APPLY (SELECT SummedMinutes - (H * 60) AS M) AS RemainderMinutes
Upvotes: 1
Reputation: 1269763
SQL Server doesn't off a time type with more than 24 hours. So, don't think of what you are doing in terms of time
. It is just a funky string representation of numbers.
So, you can parse the value into numbers, do the summation, and then reconstruct the value:
select (cast(sum(hh) + sum(mm) / 60 as varchar(255)) + ':' +
right('00' + cast(sum(mm) % 60 as varchar(255)), 2)
) as hhmm
from ( VALUES (1,N'1500:30'), (2,N'1700:50') ) t(EmployeeId, TotalWorkingTime) cross apply
(values (cast(left(TotalWorkingTime, charindex(':', TotalWorkingTime) - 1) as int),
cast(stuff(TotalWorkingTime, 1, charindex(':', TotalWorkingTime), '') as int)
)
) v(hh, mm)
Upvotes: 3
Reputation: 37473
You can try using left() and right() function for finding character before and afer ':'
select
concat
(
sum(cast(left(TotalWorkingTime,CHARINDEX(':',TotalWorkingTime)-1) as int)),
':',
case when sum(cast(right(TotalWorkingTime,CHARINDEX(':',TotalWorkingTime)-3) as int))>60 then sum(cast(right(TotalWorkingTime,CHARINDEX(':',TotalWorkingTime)-3) as int))-60 else sum(cast(right(TotalWorkingTime,CHARINDEX(':',TotalWorkingTime)-3) as int)) end
) FROM @tmpTime
Upvotes: 0