Reputation:
I have a JSON file inside a variable.
echo $JSON
{"name": "jkslave1", "nodeDescription": "This is a test agent", "numExecutors": "1", "remoteFS": "/root", "labelString": "jenkins", "mode": "NORMAL", "": ["hudson.slaves.JNLPLauncher", "hudson.slaves.RetentionStrategy$Always"], "launcher": {"stapler-class": "hudson.slaves.JNLPLauncher", "$class": "hudson.slaves.JNLPLauncher", "workDirSettings": {"disabled": false, "workDirPath": "", "internalDir": "remoting", "failIfWorkDirIsMissing": false}, "tunnel": "", "vmargs": ""}, "retentionStrategy": {"stapler-class": "hudson.slaves.RetentionStrategy$Always", "$class": "hudson.slaves.RetentionStrategy$Always"}, "nodeProperties": {"stapler-class-bag": "true"}, "type": "hudson.slaves.DumbSlave", "Jenkins-Crumb": "6af50cfe57d4685d84cc470f311fa559"}
And I want to use the variable inside my curl
command like this
curl -k -X POST "https://<JENKINS-URL>/computer/doCreateItem?name=jkslave1&type=hudson.slaves.DumbSlave" \
-H "Content-Type: application/x-www-form-urlencoded" \
-H "Jenkins-Crumb: ${CRUMB}" \
-d 'json=${JSON}'
But the above implementation gives me the ERROR
Caused: javax.servlet.ServletException: Failed to parse JSON:${JSON}
at org.kohsuke.stapler.RequestImpl.getSubmittedForm(RequestImpl.java:1022)
at hudson.model.ComputerSet.doDoCreateItem(ComputerSet.java:296)
I tried the following too
-d 'json="${JSON}"'
and also
-d 'json=\"${JSON}\"'
But it doesnt seem to work.
How can I send the JSON body to my curl command saved as a variable ?
Upvotes: 0
Views: 127
Reputation: 11
variables don't work within single quotes.
Inside single quotes everything is preserved literally, without exception.
This is well explained here
Try double quotes how you used it in the line before
Upvotes: 1