CODEWITHSUNDEEP
pythonarrayspython-3.xlist
Moid
Moid

Reputation: 440

Print list elements with difference more than a value

I have a Python list.

x = [230, 235, 300, 480, 480, 506, 515, 516]

I want to print a list with elements from Array x, with difference of more than a value(lets assume 10). So the new list will contain only elements with difference of more than 10 than the next element. The output list should contain elements which have more than 10 difference with their adjacent element in the given list. Output should be a list of [230, 300, 480, 516]

I want to make a function to make this possible.

b = [0] + x
t = []
for i in range(len(b)-1):
    if(b[i+1]-b[i]>10):
        t.append(b[i])

print(t)

I tried this. But I'm not getting proper output.

Upvotes: 1

Views: 736

Answers (4)

MJ Cipher
MJ Cipher

Reputation: 69

You can try this:

a=[230,235,300,480,480,506,515,516]
b=[0]+a
c=[]
for i in range(0,len(b)-1):
        if((b[i+1]-b[i])>10):
                c.append(b[i+1])
print(c)

Output:

[230, 300, 480, 506]

Upvotes: 1

Netwave
Netwave

Reputation: 42718

Using iterators:

import itertools
def gapFilter(l, gap_value):
  it1, it2 = itertools.tee(l)
  next(it2)
  return [x for x, y in zip(it1, it2) if abs(x-y) >= gap_value]

Here you have the live example

For getting the initial 0, just append it to the list before computing. Python3 example:

gapFilter([0, *x], 10)

Upvotes: 0

arokem
arokem

Reputation: 579

Using numpy: 

import numpy as np
xarr = np.array(x)
result = xarr[np.where(np.diff(xarr) > 10)[0]+1]

Produces: 

array([300, 480, 506])

I believe this may be what you are looking for?

Upvotes: 1

U13-Forward
U13-Forward

Reputation: 71580

Try this:

print([k for k,v in zip(x, x[1:]) if abs(k-v) > 10])

zip is your friend.

Note: this works even with the list having up and down values (meaning some times large number, and sometimes small), because i use abs.

Update:

l=[(k,v) for k,v in zip(x[1:], x) if abs(k-v) >= 10]
print([list(zip(*l))[1][0]]+list(list(zip(*l))[0]))

Works to get desired output, it's your friend now.

Upvotes: 0

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