CODEWITHSUNDEEP
ansible
vyshakh
vyshakh

Reputation: 151

replace a line in xml file using ansible

Please help me with your guidance here.

I want to comment a line in one config file and need to uncomment the other lline using ansible.

My file content as below. 

    `<include location="conf/basicUserRegistry.xml"/>`  

          this i want to comment 

`<!--include location="conf/ldapUserRegistry.xml"/-->`

         this line i want to uncomment

I tried with the below play book and its not showing any error even though its not changing any changes to the file.

- name: enable LDAP
  hosts: localhost
  tasks:
   - name: disbale basic user-registry
     lineinfile:
       path: /opt/IBM/605CLM/JazzTeamServer/server/liberty/servers/clm/server.xml
       regexp: '^\s*<include location="conf/basicUserRegistry.xml">.*$'
       line: '<!--include location="conf/basicUserRegistry.xml"-->;'
       backrefs: yes
     become: true

- name: enable LDAP USER_REGISTRY
  hosts: localhost
  tasks:
    lineinfile:
      dest: /opt/IBM/605CLM/JazzTeamServer/server/liberty/servers/clm/server.xml
      regexp: '^(.*)<!--include location="conf/ldapUserRegistry.xml"-->(.*)$'
      line: '<include location="conf/ldapUserRegistry.xml">;'
      backrefs: yes

Output:

PLAY [enable LDAP] ******************************************************************************************************************************************

TASK [Gathering Facts] ************************************************************************************************************************************** ok: [localhost]

TASK [disbale basic user-registry] ************************************************************************************************************************** ok: [localhost]

PLAY RECAP ************************************************************************************************************************************************** localhost : ok=2 changed=0 unreachable=0 failed=0

Upvotes: 1

Views: 4018

Answers (3)

Thomas Hirsch
Thomas Hirsch

Reputation: 2308

An arguably cleaner way to solve this would make use of the Ansible xml module.

Example (assuming your example showed the complete file):

tasks:
  - xml:
      file: server.xml
      xpath: /include
      attribute: location
      value: conf/ldapUserRegistry.xml

Upvotes: 2

vyshakh
vyshakh

Reputation: 151

Below is my playbook, Its not changing anything on the file 

- name: LDAP Settings
 hosts: myserver
 vars:
   mark_1: 'include location="conf/basicUserRegistry.xml"/'
   mark_2: 'include location="conf/ldapUserRegistry.xml"/'
 tasks:
    - replace:
       path: /opt/IBM/server/liberty/servers/clm/server.xml
       regexp: "^<!--{{ mark_2 }}-->"
       replace: "<{{ mark_2 }}>"
    - replace:
       path: /opt/IBM/server/liberty/servers/clm/server.xml
       regexp: "^<{{ mark_1 }}>"
       replace: "<!--{{ mark_1 }}-->"
       backup: yes'

Upvotes: 0

Vladimir Botka
Vladimir Botka

Reputation: 68034

Is this the code that you're looking for?

vars:
  mark_1: 'include location="conf/basicUserRegistry.xml"/'
  mark_2: 'include location="conf/ldapUserRegistry.xml"/'
tasks:
  - lineinfile:
      path: server.xml
      regex: "^<!--{{ mark_2 }}-->"
      line: "<{{ mark_2 }}>"
  - lineinfile:
      path: server.xml
      regex: "^<{{ mark_1 }}>"
      line: "<!--{{ mark_1 }}-->"

It's not idempotent! If the regex exists the line will replace the line found. If the regex doesn't exist the *line" will be added anyway. To make it idempotent use replace module (example below).

Or, prehaps, this one ?

  - lineinfile:
      path: server.xml
      regex: ".{{ mark_2 }}."
      line: "<{{ mark_2 }}>"
  - lineinfile:
      path: server.xml
      regex: ".{{ mark_1 }}."
      line: "<!--{{ mark_1 }}-->"

or,

  - replace:
      path: server.xml
      regexp: "^<!--{{ mark_2 }}-->"
      replace: "<{{ mark_2 }}>"
  - replace:
      path: server.xml
      regexp: "^<{{ mark_1 }}>"
      replace: "<!--{{ mark_1 }}-->"

Upvotes: 0

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