CODEWITHSUNDEEP
python
Kadence Waggoner
Kadence Waggoner

Reputation: 1

Create a list with all the words (including hyphenated words) that have more than 3 vowels

I have this string 

tw =('BenSasse, well I did teach her the bend-and-snap https://twitter.com/bethanyshondark/status/903301101855928322 QT @bethanyshondark Is Reese channeling @BenSasse https://acculturated.com/reese-witherspoons-daughter-something-many-celebrity-children-lack-work-ethic/ , Twitter for Android')

I need to create a list with all the words that have more than 3 vowels. Please help!

Upvotes: 0

Views: 67

Answers (2)

RoyM
RoyM

Reputation: 747

I would suggest you start with creating a list of all vowels:

vowels = ['a','e','i','o','u']

Well, a list of letters (Char) is really the same as a string, so I would just do the following:

vowels = "aeiou"

After that I would attempt to split your string into words. Let's try tw.split() like Joran Beasley suggested. It returns:

['BenSasse,', 'well', 'I', 'did', 'teach', 'her', 'the', 'bend-and-snap', 'https://twitter.com/bethanyshondark/status/903301101855928322', 'QT', '@bethanyshondark', 'Is', 'Reese', 'channeling', '@BenSasse', 'https://acculturated.com/reese-witherspoons-daughter-something-many-celebrity-children-lack-work-ethic/', ',', 'Twitter', 'for', 'Android']

Are you fine with this being your "words"? Notice that each link is a "word". I'm going to assume that this is fine.

Ok, so if we access each word with a for-loop, we can then access each letter with an inner for-loop. But before we start, we need to keep track of all the accepted words with 3 or more vowels, so make a new list: final_list = list(). Now:

for word in tw.split():
    counter=0 #  Let's keep track of how many vowels we have in a word
    for letter in word:
        if letter in vowels:
            counter = counter+1
    if counter >= 3:
        final_list.append(word) #  Add the word if 3 or more vowels.

If you now do a print: print(final_list) you should get:

['BenSasse,', 'bend-and-snap', 'https://twitter.com/bethanyshondark/status/903301101855928322', '@bethanyshondark', 'Reese', 'channeling', '@BenSasse', 'https://acculturated.com/reese-witherspoons-daughter-something-many-celebrity-children-lack-work-ethic/']

Upvotes: 1

blhsing
blhsing

Reputation: 106881

You can use re.findall with the following regex:

import re
re.findall(r'(?:[a-z-]*[aeiou]){3,}[a-z-]*', tw, flags=re.IGNORECASE)

This returns:

['BenSasse', 'bend-and-snap', 'bethanyshondark', 'bethanyshondark', 'Reese', 'channeling', 'BenSasse', 'acculturated', 'reese-witherspoons-daughter-something-many-celebrity-children-lack-work-ethic', 'Android']

Upvotes: 1

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